Quick question about the direction of angular momentum.

[eptheta]

When talking about the net angular momentum about where must one calculate the component due to Ω ?
Just wanted to confirm my thoughts:

Will the expression be $L_{net}=MR^2\omega$ $\hat{r} + \frac{1}{2}MR^2\Omega$ $\hat{k}$
Where $MR^2$ represents the moment of inertia about the spin axis in the radial direction and $\frac{1}{2}MR^2$ represents the moment of inertia about the diameter in the vertical direction.

Thanks.

 

[jbsteele]

Yes, that is correct. The first term is the angular momentum due to ω (the spin), and the second term is the angular momentum due to Ω (the precession).