Quick question on real analysis proof

In summary, the conversation is about proving that the sequence of functions ##x(1-x), x^2(1-x),...## converges uniformly on ##[0,1]##. The proof involves showing that ##\left(\frac{n}{n+1}\right)^n < 1## and using the fact that ##\lim_{n\to \infty} \left(1+\frac{1}{n}\right)^n = e## to indirectly prove it. However, a more direct and clear proof is provided by vanhees71. The conversation ends with a thank you and confirmation that vanhees71's proof is sufficient.
  • #1
Lee33
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0

Homework Statement



Show that the sequence of functions ##x(1-x), x^2(1-x),...## converges uniformly on ##[0,1].##

2. The attempt at a solution

I have a quick question. For the following proof why is ##\left ( \frac{n}{n+1}\right )^n < 1##?

Proof:

We need to prove that, given ##\epsilon > 0##, there exists an ##N## such that for every ##n > N## and for every ##x \in[0, 1]##, we have ##|x^n(1 - x)-0| < \epsilon.##

##x^n## and ##(1-x)## are both continuous functions. Now ##x^n(1 - x)## has a maximum on ##[0, 1]## at $x=\frac{n}{1+n}$ since ##\frac{d}{dx}[x^n(1-x)] = -x^n +nx^{n-1}-nx^n = -x-nx+n## thus ##x=\frac{n}{1+n}##.

Then ##|x^n(1-x)|<(\frac{n}{n+1})^n(\frac{1}{n+1})<\frac{1}{n+1}<\epsilon.## Choose ##N = \frac{1-\epsilon}{\epsilon}## therefore for ##n>N## we have ##|x^n(1-x)|<\epsilon.##

Why is ##\left ( \frac{n}{n+1}\right )^n < 1##?
 
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  • #2
I think that's pretty obvious, but one can of course formally prove it:
[tex]0<1 \; \Rightarrow \; n<n+1.[/tex]
Now since [itex]n+1>0[/itex] you have
[tex]\frac{n}{n+1}<1.[/tex]
Now multiplying this with [itex]n/(n+1)[/itex] gives
[tex]\left (\frac{n}{n+1} \right )^2 < \frac{n}{n+1}<1,[/tex]
and in this way you can prove that
[tex]\left (\frac{n}{n+1} \right )^k<1[/tex]
for all [itex]k \in \mathbb{N}[/itex]. Setting [itex]k=n[/itex] gives the inequality you asked for.
 
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  • #3
vanhees71 - Thanks, that is a nice way to prove it!

Is there another way, for example something similar ##\lim_{n\to \infty}(\frac{n}{n+1})^n <1## implies ##\lim_{n\to \infty} \left(1+\frac{1}{n}\right)^n = e > 1##? Or am I wrong?
 
  • #4
It has to be valid for all n>N thus your exponential limit is not going to work here.
 
  • #5
Dirk-mec1 - So I can't use that? Vanhees71 proof will suffice?
 
  • #6
Lee33 said:
vanhees71 - Thanks, that is a nice way to prove it!

Is there another way, for example something similar ##\lim_{n\to \infty}(\frac{n}{n+1})^n <1## implies ##\lim_{n\to \infty} \left(1+\frac{1}{n}\right)^n = e > 1##? Or am I wrong?
You have that backwards. The limit
$$\lim_{n\to \infty} \left(1+\frac{1}{n}\right)^n = e$$ implies that
$$\lim_{n\to \infty} \left(\frac{n}{n+1}\right)^n = \frac{1}{e} < 1.$$ You can probably use this fact in an indirect way for your needs. You know that if ##n## is large enough, ##\left(\frac{n}{n+1}\right)^n## will necessarily be less than 1 because the sequence approaches 1/e. With a suitable choice for ##N##, you will get the result you need. But why would you want to do that? The proof vanhees provided is much clearer and direct.
 
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  • #7
Vela - Thanks and you're right, vanhees proof is a lot more clear! Thanks for all the help.
 

FAQ: Quick question on real analysis proof

What is real analysis?

Real analysis is a branch of mathematics that deals with the study of real numbers and their properties. It involves the use of mathematical concepts and techniques to understand the behavior and structure of real numbers and functions.

What is a proof in real analysis?

In real analysis, a proof is a logical argument that uses mathematical concepts and axioms to demonstrate the truth of a mathematical statement. It involves a series of steps that follow a specific logical structure to show that a statement is true.

How do you approach a proof in real analysis?

When approaching a proof in real analysis, it is important to have a clear understanding of the definitions, properties, and theorems related to the topic. Then, one must carefully analyze the statement and break it down into smaller, more manageable parts. Finally, one must use logical reasoning and mathematical techniques to connect these smaller parts and arrive at a conclusion.

What are some common techniques used in real analysis proofs?

Some common techniques used in real analysis proofs include mathematical induction, proof by contradiction, and direct proof. Other techniques may involve using definitions, properties, and theorems, as well as algebraic manipulations and logical reasoning.

Why is real analysis important?

Real analysis is important because it provides a rigorous and formal framework for understanding and analyzing the behavior of real numbers and functions. It is also the foundation for many other branches of mathematics, such as calculus, differential equations, and complex analysis. Moreover, real analysis has numerous applications in various fields, including physics, engineering, and economics.

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