- #1
HeZ
- 10
- 1
Hello all,
There are a million threads and a million Google hits out there on the topic of switching the polarity of an electromagnet. Very simple stuff. But none seem to touch on the issue of inductance.
I am building a small linear actuator that will be a coil wrapped around a thin plastic tube with a cylindrical neodymium magnet in the center. So by changing the polarity of the coil I can move the magnet between two positions quickly.
I want to do this at about 100Hz and with a very fast response time, but as voltage is proportional to time derivative of current - when trying to switch the current quickly, I am expecting some very high - potentially damaging - voltage spikes.
I don't think I will just be able to hook the magnet up to a h-bridge and switch the current backwards and forwards will I? I am hoping that the field can collapse fast enough to switch it like this. I do not have any figures available to try and calculate the time constant or how much emf will be produced. But I will not need very high current. I was planning to use 6-12 volts and I only require to move a 1/4" diamteter x 1/2" length cylinder about 20mm with very little force (just quickly)
Am I thinking about this correct? Am I likely to need some extra circuitry to dissipate this emf?
Thanks,
Chris
There are a million threads and a million Google hits out there on the topic of switching the polarity of an electromagnet. Very simple stuff. But none seem to touch on the issue of inductance.
I am building a small linear actuator that will be a coil wrapped around a thin plastic tube with a cylindrical neodymium magnet in the center. So by changing the polarity of the coil I can move the magnet between two positions quickly.
I want to do this at about 100Hz and with a very fast response time, but as voltage is proportional to time derivative of current - when trying to switch the current quickly, I am expecting some very high - potentially damaging - voltage spikes.
I don't think I will just be able to hook the magnet up to a h-bridge and switch the current backwards and forwards will I? I am hoping that the field can collapse fast enough to switch it like this. I do not have any figures available to try and calculate the time constant or how much emf will be produced. But I will not need very high current. I was planning to use 6-12 volts and I only require to move a 1/4" diamteter x 1/2" length cylinder about 20mm with very little force (just quickly)
Am I thinking about this correct? Am I likely to need some extra circuitry to dissipate this emf?
Thanks,
Chris