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The Canadian Nuclear Safety Commission sets upper limits on the amounts of radiation allowable in the workplace. The maximum permissible dose for radiation workers is 5 rem (50 mSv) per year. Cobalt-60 is a radioisotope whose gamma rays are sometimes used in radiation treatment.
What is the safe working distance from an unshielded 60Co source that produces 0.800 rad per hour at a distance of 1m?
Quote your answer in metres.
Assume a 40 hour week, with a three-week holiday period per year. You will need to think about how the intensity falls off with distance; you may assume that the 60Co is a point source, and that the radiation is emitted isotropically.
I'm totally stumped with this question. I have no idea how to approach it.
I know that I have to get the units to match:
1 rad = 0.01 Gy
The equivalent dose of 50mSv per year would be 50mGy per year (assuming that the weight factor equals 1).
A friend of mine told me that the intensity is proportional to the 1/ (distance squared)... but how do I get the intensity?
Any help would be greatly appreciated!
What is the safe working distance from an unshielded 60Co source that produces 0.800 rad per hour at a distance of 1m?
Quote your answer in metres.
Assume a 40 hour week, with a three-week holiday period per year. You will need to think about how the intensity falls off with distance; you may assume that the 60Co is a point source, and that the radiation is emitted isotropically.
I'm totally stumped with this question. I have no idea how to approach it.
I know that I have to get the units to match:
1 rad = 0.01 Gy
The equivalent dose of 50mSv per year would be 50mGy per year (assuming that the weight factor equals 1).
A friend of mine told me that the intensity is proportional to the 1/ (distance squared)... but how do I get the intensity?
Any help would be greatly appreciated!