Radiation Term's Relationship to r & \lambda

In summary, the condition for the radiation term to predominate in the expression for the magnetic field is when the distance, r, is much larger than the wavelength, \lambda. This is because as r increases, the terms involving r decrease faster than the terms involving \lambda, making them negligible. The 2\pi is not "got rid of" but is included in the imaginary component of the expression.
  • #1
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Homework Statement



What is the condition for the radiation term in the expression for the field B to predominate? Express you answer as a relationship between distance r and wavelength [itex]\lambda[/itex].

B(r)=[itex]\frac{\mu_{0}I_{0}\delta l}{4\pi}[/itex]sinθ ([itex]\frac{-i\omega}{rc}[/itex]+[itex]\frac{1}{r^{2}}[/itex])exp[i(kr-[itex]\omega[/itex]t)][itex]\phi[/itex]-hat

The Attempt at a Solution



r>>[itex]\lambda[/itex]?
But how was this result obtained? If r>>c/omega, r>>c/(2[itex]\pi[/itex]f), r>>[itex]\lambda[/itex]/(2[itex]\pi[/itex]), then how was the 2[itex]\pi[/itex] got rid of?

If r>>c/[itex]\omega[/itex], why is this the case?

Please help.
 
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  • #2




The condition for the radiation term to predominate in the expression for the magnetic field, B, is when the distance, r, is much larger than the wavelength, \lambda. This can be understood by examining the terms in the expression for B and their dependence on r and \lambda.

The term sin\theta is a constant and does not depend on r or \lambda. The term -(i\omega/rc) represents the phase of the wave and is inversely proportional to r. This means that as r increases, this term decreases and becomes negligible compared to the other terms. Similarly, the term 1/r^2 decreases as r increases.

The term exp[i(kr-\omegat)] represents the amplitude of the wave and is inversely proportional to r, while directly proportional to \lambda. This means that as r increases, this term decreases, but not as quickly as the previous terms.

Now, if we consider the case where r>>\lambda, we can see that the terms involving r will become very small compared to the terms involving \lambda. This is because when r is much larger than \lambda, the decrease in the terms involving r will be much greater than the decrease in the terms involving \lambda.

To address your question about the 2\pi, it is important to note that the expression for B is a complex quantity. The 2\pi is not "got rid of" but rather is included in the imaginary component of the expression. This is because the wave is described by a complex exponential function, which has a periodicity of 2\pi.

In summary, the condition for the radiation term to predominate in the expression for the magnetic field is when r>>\lambda. This is because as r increases, the terms involving r decrease faster than the terms involving \lambda, making them negligible. The 2\pi is not "got rid of" but is included in the imaginary component of the expression.

I hope this helps clarify the condition for the radiation term to predominate. Let me know if you have any further questions.



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FAQ: Radiation Term's Relationship to r & \lambda

What is radiation term's relationship to r and λ?

The radiation term is a mathematical representation of how much energy is emitted by an object at a certain distance (r) and wavelength (λ). It describes the intensity of radiation as a function of both distance and wavelength.

How is the radiation term affected by changes in r and λ?

As r increases, the radiation term decreases because the energy is spread over a larger area. Similarly, as λ increases, the radiation term decreases because the energy is spread over a wider range of wavelengths.

What is the significance of the radiation term in scientific research?

The radiation term is important in a variety of fields, including astrophysics, atmospheric science, and nuclear physics. It helps us understand how energy is emitted, absorbed, and transferred between objects, and is crucial in studying phenomena such as black holes, the Earth's climate, and nuclear reactions.

How is the radiation term calculated?

The radiation term can be calculated using the Stefan-Boltzmann law, which relates the intensity of radiation to the temperature of an object and its emissivity (a measure of how efficiently it emits energy). The formula is I = σT4, where I is the intensity, σ is the Stefan-Boltzmann constant, and T is the temperature in Kelvin.

What are some potential applications of the radiation term?

The radiation term has practical applications in fields such as thermal imaging, remote sensing, and energy production. It is used to design and improve technologies such as infrared cameras, weather satellites, and solar panels. It also plays a role in medical imaging techniques such as X-rays and MRI scans.

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