- #1
jaydnul
- 558
- 15
I'm trying to explain an FM or AM radio receiver using photons.
When the photons are absorbed by the antenna, they arrive in discrete pulses, where in the case of FM, each wave front contains photons of the same energy (frequency) and the following wave fronts contain photons of different energies. When these photons land on the antenna in succession, the difference in energies, and therefore difference in induced voltages, is proportional to a sound signal in which the radio deciphers.
And it is essentially the same for AM, except each wave front has a different density of photons, and therefore the current modulates, not the voltage.
Is this correct? If so, wouldn't you theoretically be hearing a slightly (very slightly) sped up version of the signal if you were driving towards the radio tower, and a slightly slowed down version when driving away (since the photons are landing in succession at a faster/slower rate)?
Thanks
When the photons are absorbed by the antenna, they arrive in discrete pulses, where in the case of FM, each wave front contains photons of the same energy (frequency) and the following wave fronts contain photons of different energies. When these photons land on the antenna in succession, the difference in energies, and therefore difference in induced voltages, is proportional to a sound signal in which the radio deciphers.
And it is essentially the same for AM, except each wave front has a different density of photons, and therefore the current modulates, not the voltage.
Is this correct? If so, wouldn't you theoretically be hearing a slightly (very slightly) sped up version of the signal if you were driving towards the radio tower, and a slightly slowed down version when driving away (since the photons are landing in succession at a faster/slower rate)?
Thanks