Radius of charged particle moving in magnetic field

In summary, the problem states that a +2 helium atom was accelerated by 1700 V in a uniform magnetic field of .5T. The question asks for the radius of curvature when the particle moves in a plane perpendicular to the magnetic field. To solve for this, the velocity of the particle is needed, which can be found using the equation v = at. However, the time of acceleration is not given, making it difficult to solve the problem.
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Homework Statement


So, I got the problem from a friend who told me he copied it down in haste, so it's possible that my confusion stems from a missing variable, but I just want to be certain as my exam is in a few days. So the problem states that there's a +2 helium atom that was accelerated by 1700 V. What will be the radius of curvature if it moves in a plane perpendicular to a uniform magnetic field of .5T ?

Homework Equations


R = mv/qB
F = Eq
v = at

The Attempt at a Solution


So, the first thing I notice is that the only variable I'm not given that is needed to solve for the radius is the velocity of the particle. I'm assuming the particle started at rest and was then accelerated, so then the velocity is equal to just the acceleration times time. The acceleration could be expressed as force over mass, so then I just needed an expression for the force.

F = Eq
a = Eq/m
v = Eqt/m
R = (m/qB)(Eqt/m)

The masses cancel, the charges cancel, and I'm left with the voltage times time divided by the magnetic field.

R = Et/B

My problem is I'm not given time anywhere in the problem, but it's obviously essential to know how long the particle was accelerating. Am I missing something here?
 
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accidental post, sorry. disregard
 

FAQ: Radius of charged particle moving in magnetic field

What is the relationship between the radius of a charged particle and the strength of the magnetic field?

The radius of a charged particle moving in a magnetic field is directly proportional to the strength of the magnetic field. This means that as the strength of the magnetic field increases, the radius of the charged particle's path also increases.

How does the charge of the particle affect its radius in a magnetic field?

The charge of the particle also plays a role in determining its radius in a magnetic field. A particle with a higher charge will have a larger radius compared to a particle with a lower charge, assuming they are moving at the same speed in the same magnetic field.

Can the radius of a charged particle in a magnetic field be altered?

Yes, the radius of a charged particle can be altered by changing the strength of the magnetic field or the speed of the particle. Additionally, the radius can also be affected by changing the mass or charge of the particle.

How does the direction of the magnetic field affect the radius of a charged particle?

The direction of the magnetic field can impact the radius of a charged particle. If the magnetic field is perpendicular to the particle's velocity, the particle will move in a circular path with a constant radius. However, if the magnetic field is at an angle to the particle's velocity, the radius will be larger on one side and smaller on the other.

Is there a limit to the maximum radius a charged particle can have in a magnetic field?

There is no specific limit to the maximum radius a charged particle can have in a magnetic field. The radius will continue to increase as the strength of the magnetic field increases. However, at extremely high speeds, relativistic effects may come into play, causing deviations from the predicted radius based on classical equations.

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