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galuda
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[SOLVED] radius of synchronous satellite from a planet
A "synchronous" satellite, which always remains above the same point on a planet's equator, is put in orbit about a planet similar to Jupiter. This planet rotates once every 7.8h, has a mass of 1.8e27kg and a radius of 6.99e7. Given that G = 6.67e-11 calculate how far above jupiter's surface the satellite must be.
Kepler's 3rd law
well I converted the 7.8 hours to seconds which was 28080 seconds, then did (28080^2*g*1.8e27)/4pi^2, then took the cube root of all that. However that's not right. Any ideas?
Homework Statement
A "synchronous" satellite, which always remains above the same point on a planet's equator, is put in orbit about a planet similar to Jupiter. This planet rotates once every 7.8h, has a mass of 1.8e27kg and a radius of 6.99e7. Given that G = 6.67e-11 calculate how far above jupiter's surface the satellite must be.
Homework Equations
Kepler's 3rd law
The Attempt at a Solution
well I converted the 7.8 hours to seconds which was 28080 seconds, then did (28080^2*g*1.8e27)/4pi^2, then took the cube root of all that. However that's not right. Any ideas?