- #1
EEristavi
- 108
- 5
Problem:
We play roulette in a casino. We watch 100 rounds that result in a number between 1 and 36. and count the number of rounds for which the result is odd.
assuming that the roulette is fair, calculate the mean and deviation
Solution:
I understand that the probability - Pr = 0.5. and mean - E[x] = 50. However, I can't figure out how to write it appropriately (use formula E[x] = ∑ x * Pr)
As I Understand, I must choose random variable x = 1, but don't quite understand the "true" meaning of it and why I can't choose other variable.
Moreover, I see from solutions that σs=√(100 * 0.5 * 0.5) = 5. However, I can't understand how we get this
We play roulette in a casino. We watch 100 rounds that result in a number between 1 and 36. and count the number of rounds for which the result is odd.
assuming that the roulette is fair, calculate the mean and deviation
Solution:
I understand that the probability - Pr = 0.5. and mean - E[x] = 50. However, I can't figure out how to write it appropriately (use formula E[x] = ∑ x * Pr)
As I Understand, I must choose random variable x = 1, but don't quite understand the "true" meaning of it and why I can't choose other variable.
Moreover, I see from solutions that σs=√(100 * 0.5 * 0.5) = 5. However, I can't understand how we get this