Range of the parameter of sphere intersecting with a plane

In summary, the range of the parameter d for which the intersection of the given sphere and plane is non-empty is a ≤ d ≤ b, where a = sin\theta + cos\theta and b = 1. Alternatively, the plane will intersect the sphere if its distance from the origin is ≤ 1. This can be determined using vectors without the use of spherical coordinates.
  • #1
Jadehaan
24
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Homework Statement


Find the range of the parameter d for which the intersection of the sphere x2+y2+z2=1 and the plane x+y+z=d is non-empty.


Homework Equations


Cartesian coordinates of a sphere:
x=rcos[tex]\theta[/tex]sin[tex]\phi[/tex]
y=rsin[tex]\theta[/tex]sin[tex]\phi[/tex]
z=rcos[tex]\phi[/tex]


r=1

The Attempt at a Solution


I substitute x,y,z in both equations
d=sin[tex]\theta[/tex]sin[tex]\phi[/tex]+cos[tex]\phi[/tex]+cos[tex]\theta[/tex]sin[tex]\phi[/tex]
cos2[tex]\theta[/tex]sin2[tex]\phi[/tex]+sin2[tex]\theta[/tex]sin2[tex]\phi[/tex]+cos2[tex]\phi[/tex]=1

Since sin2[tex]\theta[/tex]+cos2[tex]\theta[/tex]=1
I get 1+cos2[tex]\phi[/tex]=1
This implies that [tex]\phi[/tex]=90
Which solves the first equation for d=sin[tex]\theta[/tex]+cos[tex]\theta[/tex]
Is this right?
Thanks for any help.
 
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  • #2
I would think your answer would need to be in the form a ≤ d ≤ b. A simpler approach might be to observe the plane will intersect the sphere if the distance of the plane from the origin is ≤ 1. This can be easily done with vectors and no need for spherical coordinates.
 

FAQ: Range of the parameter of sphere intersecting with a plane

What is the formula for finding the range of the parameter of a sphere intersecting with a plane?

The formula for finding the range of the parameter is P = (a ± √(a^2 - 4b))/2, where a and b are constants in the equation of the plane.

How does the position of the plane affect the range of the parameter?

The position of the plane can affect the range of the parameter in a few ways. If the plane is parallel to the sphere, there will be no intersection and the range will be empty. If the plane is perpendicular to the sphere, the range will be a single point. If the plane intersects the sphere at an angle, the range will be a segment of the parameter.

Can the range of the parameter ever be negative?

No, the range of the parameter cannot be negative as it represents a physical distance and cannot be measured in negative units.

What happens if the radius of the sphere is smaller than the distance between the center of the sphere and the plane?

If the radius of the sphere is smaller than the distance between the center of the sphere and the plane, there will be no intersection and the range of the parameter will be empty.

Is there a maximum range for the parameter of a sphere intersecting with a plane?

Yes, there is a maximum range for the parameter which is determined by the radius of the sphere and the distance between the center of the sphere and the plane. If the plane is parallel to the sphere, the maximum range will be equal to the radius of the sphere. If the plane intersects the sphere at an angle, the maximum range will be slightly larger than the radius of the sphere.

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