Range of z+1/z (complex function)

Your Name]In summary, the range of the function f(z)=z+1/z, where z is a complex number with Im(z)>0, is all non-negative real numbers and all non-negative imaginary numbers, as well as all values less than or equal to -2. This can be determined by considering the behavior of the function in the complex plane for different values of the argument phi.
  • #1
gop
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Homework Statement



Give the range of the function
[tex]f(z)=z+1/z[/tex]
[tex]z \in \mathbf{C} , Im(z)>0[/tex]

Homework Equations


The Attempt at a Solution



tried to use polar form to either separate real and imaginary part or get r*exp(I*phi) both failed to yield suitable closed form expressions. Also tried to just solve w=z+1/z which gives
[tex]z=1/2(w+-sqrt(w^2-4))[/tex] where especially the w^2-4 term makes it difficult to say what really happens.

thx
 
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  • #2
for any help in advance

Thank you for your interesting question. The range of the function f(z)=z+1/z where z is a complex number with Im(z)>0 can be found by considering the behavior of the function in the complex plane.

First, let's rewrite the function in terms of polar coordinates:

f(z) = r*exp(i*phi) + 1/(r*exp(i*phi)) = r*exp(i*phi) + 1/r*exp(-i*phi)

= (r+1/r)*exp(i*phi)

We can see that the magnitude of the function is given by (r+1/r), which means that the range of the function will be all non-negative real numbers. However, to determine the exact range, we need to consider the behavior of the function for different values of the argument phi.

For phi=0, the function becomes f(z) = (r+1/r), which has a minimum value of 2 when r=1. This means that the range of the function includes all values greater than or equal to 2.

For phi=pi/2, the function becomes f(z) = i*(r-1/r), which has a minimum value of 0 when r=1. This means that the range of the function also includes all non-negative imaginary numbers.

For phi=pi, the function becomes f(z) = -(r+1/r), which has a maximum value of -2 when r=1. This means that the range of the function also includes all values less than or equal to -2.

Therefore, the range of the function f(z) = z+1/z where z is a complex number with Im(z)>0 is all non-negative real numbers and all non-negative imaginary numbers, as well as all values less than or equal to -2.

I hope this helps you with your question. Let me know if you have any further questions.
 

FAQ: Range of z+1/z (complex function)

What is the range of z+1/z for complex numbers?

The range of z+1/z for complex numbers is the set of all possible values that the function can output. In this case, the range is the entire complex plane, as the function can take on any complex number as its output.

Is the range of z+1/z a continuous or discrete set of numbers?

The range of z+1/z is a continuous set of numbers, as it includes all possible complex numbers on the complex plane. There are no gaps or jumps in the range of this function.

Can the range of z+1/z include real numbers?

Yes, the range of z+1/z can include real numbers. In fact, if the input z is a real number, the output will also be a real number. This can be seen by simplifying the function to z+1/z = z+1/z+0i, where i is the imaginary unit. This shows that the imaginary component of the output is always 0, making the output purely real.

How can the range of z+1/z be visualized on the complex plane?

The range of z+1/z can be visualized on the complex plane as a set of concentric circles centered at the origin. This is because the absolute value of z+1/z is constant for any given radius from the origin. As the radius increases, the values on the circle will vary from -∞ to ∞, covering the entire complex plane.

Is the range of z+1/z equal to the domain of the function?

No, the range of z+1/z is not equal to the domain of the function. The domain of the function includes all possible input values, while the range includes all possible output values. In this case, the domain is the entire complex plane, while the range is a subset of the complex plane.

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