Rank of Two Matrices: Is [B AB ... An-1B] = [AB A2B ... AnB]?

In summary, the rank of two matrices is the maximum number of linearly independent rows or columns in the matrix, and it can be determined by performing row operations and counting the non-zero rows or columns in the resulting matrix. The rank does not change when the matrices are multiplied, and it is significant in linear algebra for determining the dimension of a vector space and the solutions of a system of linear equations. Additionally, the equality [B AB ... An-1B] = [AB A2B ... AnB] indicates that the rank of the two matrices on either side is equal, providing further insight into their properties and relationships.
  • #1
WolfOfTheSteps
138
0

Homework Statement



A is nxn
B is nxp

Is the rank of

[B AB ... An-1B]

equal to the rank of

[AB A2B ... AnB]?

If not, under what condition will the ranks be equal?

The Attempt at a Solution



I don't even know where to start. I know that both matrices should have the same number of pivots, but since this is so generalized I don't know how to learn anything about how multiplying by A would change the number of pivots!

Can someone help me out and at least give me a hint? I've been staring at this for the longest time and just don't know what to do!

Thanks!
 
Physics news on Phys.org
  • #2


my first approach would be to write out the matrices and try to find a pattern or relationship between the two. I would also look into the properties of matrix multiplication and how it affects the rank of a matrix.

One possible approach could be to consider the dimensions of the resulting matrices. Since A is nxn and B is nxp, the resulting matrices in both cases will have dimensions of nxp. This means that both matrices have the same number of columns, but the number of rows will depend on the number of matrices being multiplied.

For the first matrix [B AB ... An-1B], there will be n matrices being multiplied, so the resulting matrix will have n rows. For the second matrix [AB A2B ... AnB], there will also be n matrices being multiplied, so the resulting matrix will also have n rows.

Now, we know that the rank of a matrix is equal to the number of linearly independent rows (or columns) in the matrix. So, if we can show that the rows in both resulting matrices are linearly independent, then the ranks of the matrices will be equal.

Another approach could be to consider the null spaces of the matrices. The null space of a matrix is the set of all vectors that when multiplied by the matrix, result in a zero vector. If we can show that the null spaces of both matrices are equal, then it would mean that the ranks of the matrices are also equal.

Overall, this problem requires some knowledge of linear algebra and matrix operations. It might be helpful to review these concepts and try to apply them to this specific problem. I hope this helps!
 

FAQ: Rank of Two Matrices: Is [B AB ... An-1B] = [AB A2B ... AnB]?

What is the definition of a rank of two matrices?

The rank of a matrix is the maximum number of linearly independent rows or columns in the matrix. In other words, it is the number of rows or columns that cannot be expressed as a linear combination of other rows or columns in the matrix.

How is the rank of two matrices determined?

The rank of two matrices can be determined by performing row operations on the matrices and counting the number of non-zero rows or columns in the resulting matrix. This number will be the rank of the original two matrices.

Does the rank of two matrices change if they are multiplied?

No, the rank of two matrices does not change if they are multiplied. The rank of the resulting matrix will be equal to the rank of the original two matrices.

What is the significance of the rank of two matrices?

The rank of two matrices is important in linear algebra because it gives information about the dimension of the vector space spanned by the columns or rows of the matrix. It can also indicate whether a system of linear equations has a unique solution, no solution, or infinitely many solutions.

How does the equality [B AB ... An-1B] = [AB A2B ... AnB] relate to the rank of two matrices?

This equality indicates that the rank of the two matrices on either side of the equation is equal. In other words, the number of linearly independent rows or columns in each matrix is the same, which can provide insight into the properties and relationships of the matrices.

Back
Top