- #1
ramonegumpert
- 187
- 0
Dear Experts
We know that a capacitor is charged such that the voltage increases exponentially and tapers off as it reaches its max voltage.
I have a lithium ion bettery 4.2V. If my supply voltage is 4.2v, is it not true that :
1. As the battery is being charged nearer to 4.2v, the potential difference between the input power supply and the battery is lesser and lesser?
2. This means the flow of electrons is slowed down thus causing the Vmax 4.2v to be reached slower and slower (imagine the capacitor charging curve)?
3. If say when the battery has reached 3.9v, I increase the supply voltage to 5.5volts, would this potential difference increase help to charge faster? One the battery is fast charged to 4.2, a cutoff mechanism then kick in preventing overcharging?
Is this a good idea?
Thanks for reading.
Best regards
Ramone
We know that a capacitor is charged such that the voltage increases exponentially and tapers off as it reaches its max voltage.
I have a lithium ion bettery 4.2V. If my supply voltage is 4.2v, is it not true that :
1. As the battery is being charged nearer to 4.2v, the potential difference between the input power supply and the battery is lesser and lesser?
2. This means the flow of electrons is slowed down thus causing the Vmax 4.2v to be reached slower and slower (imagine the capacitor charging curve)?
3. If say when the battery has reached 3.9v, I increase the supply voltage to 5.5volts, would this potential difference increase help to charge faster? One the battery is fast charged to 4.2, a cutoff mechanism then kick in preventing overcharging?
Is this a good idea?
Thanks for reading.
Best regards
Ramone