- #1
vertciel
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Hello everyone:
For the following problem, I arrived at the correct answer but am unsure about the method used. Could someone please check my work to see if it is legitimate or if it is a fluke?
Thank you.
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1. The age of wine can be determined by measuring the trace amount of radioactive tritium, 3H, present in a sample. Tritium gradually diminishes by a first-order radioactive decay with a half-life of 12.5 years. If a bottle of wine is found to have a tritium concentration that is 0.100 that of freshly bottled wine, what is the age of the wine?
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My Work:
Since it takes 12.5 years for the original sample to reach 50%, I would need to find the number of half-lives needed to reach 10%.
[tex] 0.5^x = 0.1[/tex]
[tex] x ln 0.5 = ln 0.1 [/tex]
[tex] x = \frac{ln 0.1}{ln 0.5} [/tex]
Originally, I raised 12.5 to the power of
[tex] \frac{ln 0.1}{ln 0.5} [/tex], but this was incorrect since 4404 years would be unreasonable.
So instead:
[tex] 12.5 x \frac{ln 0.1}{ln 0.5} = 41.5 [/tex] years, which is the right answer.
Also, if I am indeed right, could someone please explain why I would multiply by the the number of half-lives?
For the following problem, I arrived at the correct answer but am unsure about the method used. Could someone please check my work to see if it is legitimate or if it is a fluke?
Thank you.
---
1. The age of wine can be determined by measuring the trace amount of radioactive tritium, 3H, present in a sample. Tritium gradually diminishes by a first-order radioactive decay with a half-life of 12.5 years. If a bottle of wine is found to have a tritium concentration that is 0.100 that of freshly bottled wine, what is the age of the wine?
---
My Work:
Since it takes 12.5 years for the original sample to reach 50%, I would need to find the number of half-lives needed to reach 10%.
[tex] 0.5^x = 0.1[/tex]
[tex] x ln 0.5 = ln 0.1 [/tex]
[tex] x = \frac{ln 0.1}{ln 0.5} [/tex]
Originally, I raised 12.5 to the power of
[tex] \frac{ln 0.1}{ln 0.5} [/tex], but this was incorrect since 4404 years would be unreasonable.
So instead:
[tex] 12.5 x \frac{ln 0.1}{ln 0.5} = 41.5 [/tex] years, which is the right answer.
Also, if I am indeed right, could someone please explain why I would multiply by the the number of half-lives?
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