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Homework Statement
A 10 gram silver sphere is charged until it acquired a charge of -1.2 coulomb. Find ratio of number of electron to number of proton in spere. Given that silver atomic weight and atomic number 107.87 and 47
Homework Equations
The Attempt at a Solution
first i calculated extra electron = -1.2/1.60217657 × 10-19
Since number of proton = number of elelectron before acquired charge . Number of new electron = 47 +1.2/1.60217657 × 10-19.. and then dividing it by 47 . To get the ratio . My question is that correct what i did . And if yes we he mentioned mass of silver and atomic weight.