Reaction force on a semi-cubical parabola

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A particle of mass m moves along a semi-cubical parabolic curve described by y²=4ax³ with a constant speed v. The reaction force on the particle at the point (x = 1, y = 2) can be calculated using the formula F=mv²/r, where 'r' represents the radius of curvature. The discussion highlights the need to determine 'r' for accurate calculations. A reference to a formula for finding the radius of curvature is provided, indicating that there is a straightforward method available. Understanding the radius of curvature is essential for solving the problem effectively.
zorro
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Homework Statement



A particle of mass m moves without friction along a semi-cubical parabolic curve given by y2=4ax3 with a constant speed v. The reaction force of the curve on the particle when it is at the point (x = 1, y = 2) is given approximately by

The Attempt at a Solution



F=mv2/r

How do I find out 'r' here?
 
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I suggest that the r value is the radius of curvature of the path on which the particle travels.
 
I did not ask 'what does r stand for?'! :rolleyes:
 
Have you investigated how to find the radius of curvature of a curve? There's a http://en.wikipedia.org/wiki/Radius_of_curvature_%28applications%29" that might shed some light.
 
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Oh I see!...so there is a 'ready made' formula for that. Thanks!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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