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Widow
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1. The question is as follows: "You know that unlabeled bottle contains one of the following: AgNO3, CaCl2, or Al2(SO4)3. A friend suggests that you test a portion of the bottle with Ba(NO2)3 and then with NaCl. What behavior would you expect when each of these compounds is added to the unlabeled bottle?"2.
a) AgNO3(aq) + Ba(NO2)3 (s) = AgNO3 (aq) + Ba(NO2)3 (aq)
b) CaCl2 (aq) + Ba(NO2)3 (s) = BaCl2 (aq) + Ca(NO3)2 (aq)
c) Al2(SO4)3 (aq) + 3Ba(NO2)3 (s) = 3BaSO4 (s) + 2Al(NO3)3 (aq)
However, where I am stuck is figuring out how NaCl (s) reacts with the products of those three reactions. I'm aware that the first will produce AgCl as a precipitate and the second will not produce a precipitate, but I'm finding it difficult to figure out and balance the equations with three reactants. My tries are below, but I feel as if I am doing something wrong. Any help is greatly appreciated! I'm tearing my hair out! :P3.
a) AgNO3 + Ba(NO3)2 + NaCl = NaNO3 + AgCl + BaCl2 (do I list Ba(NO3)2 and AgNO3 again as the ions can recombine?)
b) BaCl2 + Ca(NO3)2 + NaCl = NaCl + BaCl2 + NaNO3 + CaCl2
c) BaSO4 (s) + Al(NO3)3 + NaCl = Na2SO4 + NaNO3+ BaCl2 + AlCl3
a) AgNO3(aq) + Ba(NO2)3 (s) = AgNO3 (aq) + Ba(NO2)3 (aq)
b) CaCl2 (aq) + Ba(NO2)3 (s) = BaCl2 (aq) + Ca(NO3)2 (aq)
c) Al2(SO4)3 (aq) + 3Ba(NO2)3 (s) = 3BaSO4 (s) + 2Al(NO3)3 (aq)
However, where I am stuck is figuring out how NaCl (s) reacts with the products of those three reactions. I'm aware that the first will produce AgCl as a precipitate and the second will not produce a precipitate, but I'm finding it difficult to figure out and balance the equations with three reactants. My tries are below, but I feel as if I am doing something wrong. Any help is greatly appreciated! I'm tearing my hair out! :P3.
a) AgNO3 + Ba(NO3)2 + NaCl = NaNO3 + AgCl + BaCl2 (do I list Ba(NO3)2 and AgNO3 again as the ions can recombine?)
b) BaCl2 + Ca(NO3)2 + NaCl = NaCl + BaCl2 + NaNO3 + CaCl2
c) BaSO4 (s) + Al(NO3)3 + NaCl = Na2SO4 + NaNO3+ BaCl2 + AlCl3
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