Reaction Products of Ethylene with Fluorine Gas

[tandoorichicken]

just a basic rookie question. What are the products when ethylene reacts with fluorine gas (i.e., burned in presence of fluorine)?

I was given the following data:
$H_2 + F_2 \rightarrow 2HF \Delta H^{o} = -537 kJ$
$C + 2F_2 \rightarrow CF_4 \Delta H^{o} = -680 kJ$
$2C + 2H_2 \rightarrow C_2 H_4 \Delta H^{o} = +52.3 kJ$

I used the starting formula $C_2 H_4 + 4F_2$

I balanced out equations and got two possibilities, and I'm not sure which one to go with. In one, it forms 2 hydrogen molecules and 2 carbon tetrafluoride, and in the other it forms 1 C, 2 HF and 1 carbon tetrafluoride. BOTH of these balance out and I don't know which one to go with.

 

[dextercioby]

Since the Fluorine is the most reactive element among the electronegative/nonmetal ones,i'd say that both reactions are in theory possible,since the fluorine has the power to knock both C and H from such compounds.However,i think that it may add(itonate ..??,is this the word) to the C_{2}H_{4} breaking the double bond and resulting something like
C_{2}F_{2}H_{2}.However,i find the second reaction (almost) impossble.

Daniel.

P.S.Any chemist is invited to express his/her opinion.

 

[wais]

The reaction between ethylene (C2H4) and fluorine gas (F2) can result in two possible products depending on the reaction conditions. The first possibility is the formation of 2 hydrogen molecules (H2) and 2 carbon tetrafluoride (CF4) molecules. This reaction is balanced by the equation C2H4 + 4F2 → 2H2 + 2CF4. The second possibility is the formation of 1 carbon (C) atom, 2 hydrogen fluoride (HF) molecules, and 1 carbon tetrafluoride (CF4) molecule. This reaction is balanced by the equation C2H4 + 4F2 → C + 2HF + CF4. Both reactions are exothermic, meaning they release heat energy.

The choice between the two reactions depends on the reaction conditions, such as temperature and pressure. At high temperatures and low pressures, the first reaction is favored and will likely produce more products. On the other hand, at low temperatures and high pressures, the second reaction is favored and will likely produce more products.

It is important to note that both reactions are possible and can occur simultaneously, resulting in a mixture of the two products. The exact ratio of the products will depend on the reaction conditions. Additionally, there may also be other minor products formed, such as carbon monofluoride (CF) and carbon difluoride (CF2).

In summary, the reaction between ethylene and fluorine gas can result in the formation of 2H2 + 2CF4 or C + 2HF + CF4 depending on the reaction conditions. Both reactions are exothermic and can occur simultaneously, producing a mixture of products.