- #1
Scousergirl
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I'm having a little difficulty understanding Epsilon in the definition of convergence. From what the book says it is any small real number greater than zero (as small as you can imagine?). Also, since I don't quite grasp what this epsilon is and how it helps define convergence, I am having difficulty applying it to the following problem:
Let b=Least upper bound of a set S (S is a subset of the real numbers) that is bounded and non empty. Then Given epsilon greater than 0, there exists an s in S such that (b-Epsilon)<= s <= b.
I started by proving that there exists an s in S, but I cannot figure out how to relate this all to epsilon. What is confusing me I guess is the actual definition of S. Can the set {1*, b} satisfy the requirements of s (it is a subset of the real numbers, bounded above by b and non empty) but then how do we show that the statement is true for s=1*. Also, b doesn't have to part of S right?
Let b=Least upper bound of a set S (S is a subset of the real numbers) that is bounded and non empty. Then Given epsilon greater than 0, there exists an s in S such that (b-Epsilon)<= s <= b.
I started by proving that there exists an s in S, but I cannot figure out how to relate this all to epsilon. What is confusing me I guess is the actual definition of S. Can the set {1*, b} satisfy the requirements of s (it is a subset of the real numbers, bounded above by b and non empty) but then how do we show that the statement is true for s=1*. Also, b doesn't have to part of S right?
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