- #1
mathdad
- 1,283
- 1
Find all real solutions of the equation.
x - sqrt {x^2 - x} = sqrt {x}, where x > 0.
Since x cannot be 0, I divided through by sqrt {x} to simplify the equation.
I did a lot of math on paper and ended up with x = 1 as the answer.
I decided to substitute x = 1 into the original equation.
1 - sqrt {1^2 - 1} = sqrt {1}
1 - sqrt {1 - 1} = 1
1 - sqrt {0} = 1
1 - 0 = 1
1 = 1
What do you say?
x - sqrt {x^2 - x} = sqrt {x}, where x > 0.
Since x cannot be 0, I divided through by sqrt {x} to simplify the equation.
I did a lot of math on paper and ended up with x = 1 as the answer.
I decided to substitute x = 1 into the original equation.
1 - sqrt {1^2 - 1} = sqrt {1}
1 - sqrt {1 - 1} = 1
1 - sqrt {0} = 1
1 - 0 = 1
1 = 1
What do you say?