- #1
Grasshopper
Gold Member
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- TL;DR Summary
- Movies and other media depict stars moving by as if you were on a boat. What does it really look like?
I have my own intuition on things, which I hope to correct if I’m wrong.
For example, the most obvious thing is that stars won’t fly in a straight line from the front of the craft to the back if you look out the side window because the craft would be rotating to simulate Earth’s gravity.
So, assuming the ship moves forward perpendicularly to its rotation, if you’re looking out the side window, the stars should move from up to down, should they not? The spaceship pushes up against your feet to simulate gravity, so the ship is rotating “upwards,” so the stars move downwards (and back, over long periods of time as the ship moves toward its destination). And then they appear again up high on the window after a rotation is completed, just like what happens here on Earth.
If this is true, would you see the stars somewhat blue shifted when they are up high in the window and red shifted when they are low in the window? I reason that because when they are high in the window, you are momentarily moving toward them, and when they’re low you’re momentarily moving away.
Unless I’m envisioning it wrong. Or unless the rotation would have to be absurd to notice a difference.
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If, on the other hand, you look in the direction the ship is traveling (perpendicular to the rotation), the stars ought to just move in circles across your window, right?I guess I can see why media tends to show stars flying by from the front of the craft to the back. It makes it look like the craft is going forward. But surely a real starship would be constantly rotating.
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Lastly, is there a formula that tells what the magnitude of rotation must be in order to simulate 1 G that is dependent on the radius and/or mass of the starship? I’m thinking you want 9.8m/s^2, but if you have a really big ship, maybe somewhat less. Earth’s rotation is only 0.039 m/s^2 if I recall correctly. I guess an angular velocity to force equation would show the way.
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As always, thanks! And any further insight or corrections are appreciated.
For example, the most obvious thing is that stars won’t fly in a straight line from the front of the craft to the back if you look out the side window because the craft would be rotating to simulate Earth’s gravity.
So, assuming the ship moves forward perpendicularly to its rotation, if you’re looking out the side window, the stars should move from up to down, should they not? The spaceship pushes up against your feet to simulate gravity, so the ship is rotating “upwards,” so the stars move downwards (and back, over long periods of time as the ship moves toward its destination). And then they appear again up high on the window after a rotation is completed, just like what happens here on Earth.
If this is true, would you see the stars somewhat blue shifted when they are up high in the window and red shifted when they are low in the window? I reason that because when they are high in the window, you are momentarily moving toward them, and when they’re low you’re momentarily moving away.
Unless I’m envisioning it wrong. Or unless the rotation would have to be absurd to notice a difference.
—-
If, on the other hand, you look in the direction the ship is traveling (perpendicular to the rotation), the stars ought to just move in circles across your window, right?I guess I can see why media tends to show stars flying by from the front of the craft to the back. It makes it look like the craft is going forward. But surely a real starship would be constantly rotating.
——
Lastly, is there a formula that tells what the magnitude of rotation must be in order to simulate 1 G that is dependent on the radius and/or mass of the starship? I’m thinking you want 9.8m/s^2, but if you have a really big ship, maybe somewhat less. Earth’s rotation is only 0.039 m/s^2 if I recall correctly. I guess an angular velocity to force equation would show the way.
—-
As always, thanks! And any further insight or corrections are appreciated.