Rearranging Equations: 3x^2 + 2y^2 = 35

[Stratosphere]

Homework Statement

3x^{2} + 2y^{2} = 35

Homework Equations

The Attempt at a Solution

I rearrangged it for x^{2} and got -\frac{2}{3}y+11\frac{2}{3}=x^{2}
Is this right?

 

[rock.freak667]

It looks correct to me

 

[cshum00]

I don't think it is 11(2/3)

3x^2 + 2y^2=35
3x^2 = 35 - 2y^2
x^2 = 35/3 - (2/3)y^2

but 35/3 = 11(2/3)?
11.66.. \neq 7.33..

 

[rock.freak667]

I don't think it is 11(2/3)

3x^2 + 2y^2=35
3x^2 = 35 - 2y^2
x^2 = 35/3 - (2/3)y^2

but 35/3 = 11(2/3)?
11.66.. \neq 7.33..

I believe 11\frac{2}{3} meant 11 and 2/3 not 11 multiplied by 2/3

 

[HallsofIvy]

But it should be
x^2= -\frac{2}{3}y^2- 11\frac{2}{3}
Not
x^2= -\frac{2}{3}y- 11 \frac{2}{3}

I presume the missing exponent on y was a typo.

 

[cshum00]

I believe 11\frac{2}{3} meant 11 and 2/3 not 11 multiplied by 2/3

lol. Mixed numbers. It has been so long since i last used them and it should be best to be avoided.