Reducing the Wave Equation: Change of Variables

In summary, by using the change of variables \xi=x-\alpha t and \eta=x+\alpha t, the wave equation u_{tt}-\alpha^{2}u_{xx}=0 can be reduced to the form \phi_{\xi \eta}=0. The necessary substitutions for \frac{\partial \xi}{\partial t}, \frac{\partial^{2}\xi}{\partial t^{2}}, \frac{\partial \xi}{\partial x}, \frac{\partial^{2}\xi}{\partial x^{2}}, \frac{\partial \eta}{\partial t}, and \frac{\partial^{2}\xi}{\partial x^{2}} are made, and after substituting into the original
  • #1
K29
108
0

Homework Statement



Show that the wave equation [itex]u_{tt}-\alpha^{2}u_{xx}=0[/itex] can be reduced to the form [itex]\phi_{\xi \eta}=0[/itex] by the change of variables
[itex]\xi=x-\alpha t[/itex]
[itex]\eta=x+\alpha t[/itex]

The Attempt at a Solution



[itex]\frac{\partial u}{\partial t}=\frac{\partial \xi}{\partial t}\frac{\partial \phi}{\partial \xi}+\frac{\partial \eta}{\partial t}\frac{\partial \phi}{\partial \eta}[/itex] (chain rule)
[itex]\frac{\partial^{2} u}{\partial t^{2}}=\frac{\partial}{\partial t}(\frac{\partial \xi}{\partial t}\frac{\partial \phi}{\partial \xi} + \frac{\partial \eta}{\partial t} \frac{\partial \phi}{\partial \eta})[/itex]
After some use of chain rule and product rule I get:
[itex]\frac{\partial^{2} u}{\partial t^{2}}= \frac{\partial^{2}\xi}{\partial t^{2}}\frac{\partial\phi}{\partial\xi} + \left(\frac{\partial \xi}{\partial t}\right)^{2} \frac{\partial^{2}\phi}{\partial \xi^{2}} + \frac{\partial^{2}\eta}{\partial t^{2}}\frac{\partial\phi}{\partial\eta} + \left(\frac{\partial \eta}{\partial t}\right)^{2} \frac{\partial^{2}\phi}{\partial \eta^{2}}[/itex] (1)
Similarly
[itex]\frac{\partial^{2} u}{\partial x^{2}}=\frac{\partial^{2}\xi}{\partial x^{2}}\frac{\partial\phi}{\partial\xi} + \left(\frac{\partial \xi}{\partial x}\right)^{2}\frac{\partial^{2}\phi}{\partial \xi^{2}}+\frac{\partial^{2}\eta}{\partial x^{2}}\frac{\partial\phi}{\partial\eta} + \left(\frac{\partial \eta}{\partial x}\right)^{2}\frac{\partial^{2}\phi}{\partial \eta^{2}}[/itex] (2)
Making the substitutions:
[itex]\frac{\partial \xi}{\partial t}=-\alpha[/itex], [itex]\frac{\partial^{2}\xi}{\partial t^{2}}=0[/itex]
[itex]\frac{\partial \xi}{\partial x}=1[/itex], [itex]\frac{\partial^{2}\xi}{\partial x^{2}}=0[/itex]
and
[itex]\frac{\partial \eta}{\partial t}=\alpha[/itex], [itex]\frac{\partial^{2}\xi}{\partial t^{2}}=0[/itex]
[itex]\frac{\partial \eta}{\partial x}=1[/itex], [itex]\frac{\partial^{2}\xi}{\partial x^{2}}=0[/itex]

Substituting these into (1) and (2) and substituting (1) and (2) into the original wave equation we get:
[itex]\alpha^{2}\frac{\partial^{2}\phi}{\partial \xi^{2}}+\alpha^{2}\frac{\partial^{2} \phi}{\partial \eta^{2}}-\alpha^{2}\left(\frac{\partial^{2}\phi}{\partial \xi^{2}}+\frac{\partial^{2}\phi}{\partial\eta^{2}}\right)=0[/itex]

[itex]0=0[/itex]

Has something gone wrong here? Please help. Thanks
 
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  • #2
Hi K29! :wink:

I don't follow this. :confused:

First, u is not necessarily equal to φ … keep with u until the end!

Second, you seem to have used the chain rule for ∂/∂t (and ∂/∂x) the first time, but not for the second time (which you haven't copied)

Start again. :smile:
 
  • #3
K29 said:

Homework Statement



Show that the wave equation [itex]u_{tt}-\alpha^{2}u_{xx}=0[/itex] can be reduced to the form [itex]\phi_{\xi \eta}=0[/itex] by the change of variables
[itex]\xi=x-\alpha t[/itex]
[itex]\eta=x+\alpha t[/itex]


The Attempt at a Solution



[itex]\frac{\partial u}{\partial t}=\frac{\partial \xi}{\partial t}\frac{\partial \phi}{\partial \xi}+\frac{\partial \eta}{\partial t}\frac{\partial \phi}{\partial \eta}[/itex] (chain rule)
[itex]\frac{\partial^{2} u}{\partial t^{2}}=\frac{\partial}{\partial t}(\frac{\partial \xi}{\partial t}\frac{\partial \phi}{\partial \xi} + \frac{\partial \eta}{\partial t} \frac{\partial \phi}{\partial \eta})[/itex]
After some use of chain rule and product rule I get:
[itex]\frac{\partial^{2} u}{\partial t^{2}}= \frac{\partial^{2}\xi}{\partial t^{2}}\frac{\partial\phi}{\partial\xi} + \left(\frac{\partial \xi}{\partial t}\right)^{2} \frac{\partial^{2}\phi}{\partial \xi^{2}} + \frac{\partial^{2}\eta}{\partial t^{2}}\frac{\partial\phi}{\partial\eta} + \left(\frac{\partial \eta}{\partial t}\right)^{2} \frac{\partial^{2}\phi}{\partial \eta^{2}}[/itex] (1)
Similarly
[itex]\frac{\partial^{2} u}{\partial x^{2}}=\frac{\partial^{2}\xi}{\partial x^{2}}\frac{\partial\phi}{\partial\xi} + \left(\frac{\partial \xi}{\partial x}\right)^{2}\frac{\partial^{2}\phi}{\partial \xi^{2}}+\frac{\partial^{2}\eta}{\partial x^{2}}\frac{\partial\phi}{\partial\eta} + \left(\frac{\partial \eta}{\partial x}\right)^{2}\frac{\partial^{2}\phi}{\partial \eta^{2}}[/itex] (2)
Making the substitutions:
[itex]\frac{\partial \xi}{\partial t}=-\alpha[/itex], [itex]\frac{\partial^{2}\xi}{\partial t^{2}}=0[/itex]
[itex]\frac{\partial \xi}{\partial x}=1[/itex], [itex]\frac{\partial^{2}\xi}{\partial x^{2}}=0[/itex]
and
[itex]\frac{\partial \eta}{\partial t}=\alpha[/itex], [itex]\frac{\partial^{2}\xi}{\partial t^{2}}=0[/itex]
[itex]\frac{\partial \eta}{\partial x}=1[/itex], [itex]\frac{\partial^{2}\xi}{\partial x^{2}}=0[/itex]

Substituting these into (1) and (2) and substituting (1) and (2) into the original wave equation we get:
[itex]\alpha^{2}\frac{\partial^{2}\phi}{\partial \xi^{2}}+\alpha^{2}\frac{\partial^{2} \phi}{\partial \eta^{2}}-\alpha^{2}\left(\frac{\partial^{2}\phi}{\partial \xi^{2}}+\frac{\partial^{2}\phi}{\partial\eta^{2}}\right)=0[/itex]

[itex]0=0[/itex]

Has something gone wrong here? Please help. Thanks

How come you not getting any mixed-partials in there. I don't see a single one. Gonna' need some right? I think I know what the problem is but not sure but it's one that gets lots of students and also, I don't know about you but that phi thing just gets in the way for me. Isn't it really just:

[tex]\frac{\partial u}{\partial t}=\frac{\partial u}{\partial \xi} \frac{\partial \xi}{\partial t}+\frac{\partial u}{\partial \eta} \frac{\partial \eta}{\partial t}[/tex]

Now when you do the second partial you get terms like:

[tex]\frac{\partial}{\partial t}\left(\frac{\partial u}{\partial \xi}\right)[/tex]

What exactly is that?
 
  • #4
Thanks for the help. Solved :)
 

FAQ: Reducing the Wave Equation: Change of Variables

What is a PDE?

A PDE, or partial differential equation, is a mathematical equation that involves multiple variables and their partial derivatives. It is typically used to describe physical phenomena, such as the movement of fluids or the propagation of waves.

What is the wave equation?

The wave equation is a type of PDE that describes the behavior of waves, such as sound waves or electromagnetic waves. It relates the second derivative of a wave's position to its second derivative in time, and is used to model wave propagation in various fields of science and engineering.

How does reducing the wave equation help with solving it?

Reducing the wave equation means simplifying it by removing any unnecessary terms or variables. This can make the equation easier to solve and understand, as well as help identify any special or unique solutions.

What are some common methods for reducing the wave equation?

Some common methods for reducing the wave equation include separation of variables, Fourier transform, and Laplace transform. These methods involve manipulating the equation to isolate certain variables or transform it into a more manageable form.

Why are PDEs and the wave equation important in science?

PDEs and the wave equation are important in science because they provide a mathematical framework for understanding and predicting the behavior of physical systems. They are used in fields such as physics, engineering, and economics to model and analyze various phenomena, and have led to many advancements and discoveries in these fields.

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