- #1
Moogie
- 168
- 1
Hi
When you are reducing benzophenone to diphenylethanol you use 4 moles of sodium borohydride. I don't know how you would write this as an equation because I don't know what the sodium borohydride becomes. It has lost 4 hydride ions and is just with a sodium and boron. Also, you haven't made the alcohol at this stage yet either - you have an intermediate with an O- species in it. YOu don't form the alchol until the acid work up step
How would i write a balanced equation for this stage of the reaction?
e.g. NaBH4 + 4Benzonphenone etc
thanks
When you are reducing benzophenone to diphenylethanol you use 4 moles of sodium borohydride. I don't know how you would write this as an equation because I don't know what the sodium borohydride becomes. It has lost 4 hydride ions and is just with a sodium and boron. Also, you haven't made the alcohol at this stage yet either - you have an intermediate with an O- species in it. YOu don't form the alchol until the acid work up step
How would i write a balanced equation for this stage of the reaction?
e.g. NaBH4 + 4Benzonphenone etc
thanks