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http://math.stackexchange.com/quest...ese-angles-equal-for-object-on-inclined-planeTyrannosaurus_ said:
The angle of incline of an inclined plane plays a crucial role in determining the weight of an object on the plane. As the angle of incline increases, the component of the weight acting perpendicular to the surface of the plane also increases. This means that the weight of the object appears to be greater when the angle of incline is steeper.
The center of mass (COM) of an object on an inclined plane is affected by the angle of incline. As the angle of incline increases, the force of gravity acting on the object shifts, causing the COM to move closer to the base of the inclined plane. This is because the steeper the incline, the greater the component of the weight acting in the downward direction.
No, the weight of an object on an inclined plane cannot be greater than its actual weight. However, as mentioned earlier, the perceived weight of the object may be greater due to the angle of incline and the shift in the force of gravity.
The angle of incline is a crucial factor in determining the forces in a FBD on an inclined plane. The weight of the object, which is always acting straight downwards, needs to be resolved into its components parallel and perpendicular to the plane. These components then affect the other forces in the FBD, such as friction and normal force.
Yes, there is an optimal angle of incline for an object on an inclined plane to experience the minimum weight. This angle is equal to 90 degrees, meaning that the plane is completely vertical. In this case, the weight of the object is acting directly downwards, and there is no component of the weight acting parallel to the plane. However, this is not a practical angle for most applications, and a shallower angle of incline is often used to minimize the weight of an object on an inclined plane.
