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OneObstacle
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I was looking back at some homework solutions I've solved earlier this term and I ran across this equation:
Δt = 2*Δx/(vf+vi)
Which seems to translate to:
Δt = Δx/vave
Is this an actual way of finding delta t? I got the answer right, but I can not understand or find where I got this equation.
EDIT: Can someone take this down? I found out I just rearranged d = (vf+vi)/2 * t
Δt = 2*Δx/(vf+vi)
Which seems to translate to:
Δt = Δx/vave
Is this an actual way of finding delta t? I got the answer right, but I can not understand or find where I got this equation.
EDIT: Can someone take this down? I found out I just rearranged d = (vf+vi)/2 * t
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