- #1
RoxSox2004
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Homework Statement
A pipe, open at one end, has a leng
produces pipe A, open at one end, and pipe B, o
A pipe, open at one end, has a length L. Cutting this pipe crosswise
produces pipe A, open at one end, and pipe B, open at both ends.
a. For what length of pipe A will the third lowest resonant frequency of pipe A be equal
to the lowest resonant frequency of pipe B?
Homework Equations
v = (lambda)(f)
5th harmonic of A, f = (5v)/(4L)
1st Harmonic of B, f = v/2L
The Attempt at a Solution
I've been fairly stumped by this one. I don't get exactly how to set it up. I tried setting the frequencies equal to each other, but it doesn't work.