- #1
Decimal
- 75
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Hello,
I am encountering some confusion with the relation between the latent heat of vaporization and the temperature of a substance. I understand both the latent heat and the entropy change of vaporization are dependent on the temperature, assuming the pressure is held constant. However given that the change in Gibbs energy for a phase change is equal to zero, one can express the boiling point of a substance in the latent heat and entropy change: $$ \Delta g = l_{23} - T_{boil} s_{23} = 0$$ $$T_{boil} = \frac {l_{23}}{s_{23}}$$ Here 2 and 3 refer to the fluid and gas states of the substance respectively. Doesnt this imply that the boiling point of a substance is dependent on the temperature? How can I interpret this? I always thought of the boiling point as a quantity dependent on the outside pressure.
Thanks!
I am encountering some confusion with the relation between the latent heat of vaporization and the temperature of a substance. I understand both the latent heat and the entropy change of vaporization are dependent on the temperature, assuming the pressure is held constant. However given that the change in Gibbs energy for a phase change is equal to zero, one can express the boiling point of a substance in the latent heat and entropy change: $$ \Delta g = l_{23} - T_{boil} s_{23} = 0$$ $$T_{boil} = \frac {l_{23}}{s_{23}}$$ Here 2 and 3 refer to the fluid and gas states of the substance respectively. Doesnt this imply that the boiling point of a substance is dependent on the temperature? How can I interpret this? I always thought of the boiling point as a quantity dependent on the outside pressure.
Thanks!