- #1
Ace.
- 52
- 0
Homework Statement
We calculated times of the periods of varying pendulum lengths. (20cm, 40cm, 60cm, 80cm). Then the frequency was calculated for each length and then a frequency-length graph was made. Since the graph is an exponential relationship we graphed our values on a log-log chart. Then we found the equation y = kxn, where k is the value of y where x = 1, and n is the slope.
the following equation was found from the log-log chart, wehre f is the frequency and L is the length:
[itex]f = 1.5L^{-0.5}[/itex]
What is the equation that relates frequency to length in a pendulum?
Homework Equations
[itex]T = 2\pi\sqrt{\frac{L}{g}}[/itex]
[itex]f = 1.5L^{-0.5}[/itex]
The Attempt at a Solution
I can come up with the equation for f from using the first equation
[itex]\frac{1}{f} = 2\pi\sqrt{\frac{L}{g}}[/itex]
[itex]f = \frac{1}{2\pi\sqrt{\frac{L}{g}}}[/itex]
But my issue is does the equation I found for my log-log chart ([itex]f = 1.5L^{-0.5}[/itex]) play any role in finding the relationship? What is the significance of this equation? Would there be a way to derive [itex]f = \frac{1}{2\pi\sqrt{\frac{L}{g}}}[/itex] using it?