- #1
MickeyBlue
- 26
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Homework Statement
The Higher Heating Value (HHV) of gaseous propane is given as 2220.0 kJ/mol. What is the value of the Lower Heating Value (LHV) of gaseous propane?
Data for water (all in kJ/mol):
H(g, 25 deg. C) = 45.85 ;
H(g, 100 deg. C) = 48.17 ;
H(l, 25 deg. C) = 1.886 ;
H(l, 100 deg. C) = 7.544 ;
∆Hvap(25 deg. C) = 43.97 ;
∆Hvap(100 deg. C) = 40.63
A. 2057 kJ/mol
- B. 2387 kJ/mol
- C. 2044 kJ/mol
- D. 2014 kJ/mol
- E. 2035 kJ/mol
Homework Equations
HHV = LHV + nΔHvap
I know LHV is HHV less heat of vaporisation of water, but the idea of calculating from what I think is the reference state is confusing me. I realize I may be missing something obvious, but we didn't spend long covering this topic.
The Attempt at a Solution
LHV = HHV - nΔHvap
LHV = (2220) - Hsensible - (ΔHvap - ΔHvap, ref))
= (2220) - (7.544 - 1.886) - (40.63 - 43.97)
= 2218 kJ/mol