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Minhtran1092
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Homework Statement
Two capacitor plates (infinite plane) with uniform charge distribution but different charges (one positive, one negative) are distance "d" apart. A charge is place at d/2 and feels force |F1|. A charge is placed at d/4 and feels force |F2|. How does |F1| compare to |F2|?
Homework Equations
F=qE (Force on a test charge is proportional to the electric field at the point charge)
E = η/ε0 (η = Q/A, charge distribution); Electrical field between two parallel plate capacitors
The Attempt at a Solution
The electrical field between two parallel plate capacitors is constant and uniform in direction at any point. Since F=qE, E is constant and 'q' is negligible, F≈E everywhere. Thus, |F1|=|F2|.
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