- #1
Somali_Physicist
- 117
- 13
Hello fellow physicists.Recently I imagined a particle far away from everything (infinitely away) such that there is no potential energy affecting the particle.
Ep = 0
Ek = mc2δ : δ = (1-v2/c2)-1/2
L = EP- Ek
= -mc2δ
∂L/∂v = vE0/c2 *δ^3 where E0 = mc2
d( ∂L/∂x)/dt = 0
∴
vE0/c2 *δ^3 = 0
mvδ3 = 0
I'm not 100% sure if next lines are correct
p = mvδ
∴ pδ2 = 0
∴
p = 0 ⇒ m = 0 or v = 0
δ = 0
(1-v2/c2)-1/2 = 0
v = c ⇒ m =0
Inconclusion a particle with zero potential is at velocity = 0 , what does this mean? a particle unmoving means absolute temperature has been reached!
vrms = (3RT/m)1/2
T = mvrms*1/3R
T ⇒ 0 as Ep ⇒ 0
Other solution states
Light or massless particles travel in a purely kinetic environment. I will update this with reference to both its wave like instances as well as its photon like instances.
Please criticize this as I wish to learn.
-SomaliPhysicist.
Ep = 0
Ek = mc2δ : δ = (1-v2/c2)-1/2
L = EP- Ek
= -mc2δ
∂L/∂v = vE0/c2 *δ^3 where E0 = mc2
d( ∂L/∂x)/dt = 0
∴
vE0/c2 *δ^3 = 0
mvδ3 = 0
I'm not 100% sure if next lines are correct
p = mvδ
∴ pδ2 = 0
∴
p = 0 ⇒ m = 0 or v = 0
δ = 0
(1-v2/c2)-1/2 = 0
v = c ⇒ m =0
Inconclusion a particle with zero potential is at velocity = 0 , what does this mean? a particle unmoving means absolute temperature has been reached!
vrms = (3RT/m)1/2
T = mvrms*1/3R
T ⇒ 0 as Ep ⇒ 0
Other solution states
Light or massless particles travel in a purely kinetic environment. I will update this with reference to both its wave like instances as well as its photon like instances.
Please criticize this as I wish to learn.
-SomaliPhysicist.