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virgil1612
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- Photons do not have rest mass, but do they have "relativistic", or "effective", or "dynamic" mass?
Photons have 0 rest mass. But could I talk about relativistic, or dynamic photon mass, that would be the solution of
hf = mc^2 ? The relativistic mass would be m = m0/sqrt(1-v^2/c^2), where m0 is the rest mass, so 0, and v = c, so the denominator is also 0. The previous equations would give 0/0, so indeterminate, and could have a finite value. Am I allowed to think in these terms?
Thanks, Virgil.
hf = mc^2 ? The relativistic mass would be m = m0/sqrt(1-v^2/c^2), where m0 is the rest mass, so 0, and v = c, so the denominator is also 0. The previous equations would give 0/0, so indeterminate, and could have a finite value. Am I allowed to think in these terms?
Thanks, Virgil.