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Hirams_bro
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In my Mechanics of Materials book by Hibbeler, it discusses residual stress loading diagrams.
I'm sure anyone who has taken a Strenths of Materials course will remember the classic problem in residual stress analysis of a statically indeterminate bar between two fixed supports with an external load acting somewhere along its length. Here is a crude diagram. Beam
______________________________________
Fb ---->|________|<---P________________|<----- FaFb and Fa are support forces, and P is external loading applied at some point along the member.
On every loading diagram of this sort it they first create a stress-strain diagram for the loading and unloading phase with one side of the member usually going plastic during loading while the other remains elastic.
Now, my book says to create the unloading part of the diagram and find the residual stress we remove the external load P "which is equivalent to reversing P in the opposite direction as it was during loading."
My question is, how does removing the external load equate to reversing it? How are those two the same thing? I asked my professor this, but he is literally a semester away from retirement and doesn't really answer questions of this sort too well.
I'm sure anyone who has taken a Strenths of Materials course will remember the classic problem in residual stress analysis of a statically indeterminate bar between two fixed supports with an external load acting somewhere along its length. Here is a crude diagram. Beam
______________________________________
Fb ---->|________|<---P________________|<----- FaFb and Fa are support forces, and P is external loading applied at some point along the member.
On every loading diagram of this sort it they first create a stress-strain diagram for the loading and unloading phase with one side of the member usually going plastic during loading while the other remains elastic.
Now, my book says to create the unloading part of the diagram and find the residual stress we remove the external load P "which is equivalent to reversing P in the opposite direction as it was during loading."
My question is, how does removing the external load equate to reversing it? How are those two the same thing? I asked my professor this, but he is literally a semester away from retirement and doesn't really answer questions of this sort too well.
Homework Statement
Homework Equations
The Attempt at a Solution
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