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highschoolstudent454
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Mentor note: Moved from a technical section, so is missing the homework template.
A Body of mass 1kg moves with a uniform velocity of magnitude 12m/s, a resistance of force of magnitude 6x^2 (newton) where x is the displacement (meter) which the body travels under the action of the resistance acts on it.
1) Find the work done by the resistance until x=4
2) Find the velocity of the body and its kinetic energy at x=2
I have no problem in solving the question. However, I have some difficulty in describing motion over the change of x. I got the kinetic energy to be T = 72 - 2x^3 (after integrating with respect to x). Does this mean that the body will stop at x = 36^(1/3) < 4 as all initial kinetic energy will be consumed or will the body move in the opposite direction in the direction of the acting resistance? in other words, will the body continue to move in the opposite direction or stop, and thus the first requirement would be meaningless?
A Body of mass 1kg moves with a uniform velocity of magnitude 12m/s, a resistance of force of magnitude 6x^2 (newton) where x is the displacement (meter) which the body travels under the action of the resistance acts on it.
1) Find the work done by the resistance until x=4
2) Find the velocity of the body and its kinetic energy at x=2
I have no problem in solving the question. However, I have some difficulty in describing motion over the change of x. I got the kinetic energy to be T = 72 - 2x^3 (after integrating with respect to x). Does this mean that the body will stop at x = 36^(1/3) < 4 as all initial kinetic energy will be consumed or will the body move in the opposite direction in the direction of the acting resistance? in other words, will the body continue to move in the opposite direction or stop, and thus the first requirement would be meaningless?
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