Resolving Forces for Periodic Motion in a Suitcase

In summary: The second expression (Fn) will be smaller than the first because the centrifugal force is smaller than the gravity force. The net force on the object (F) will be the smaller of the two forces.
  • #1
Angello90
65
0
Hi all,

Everything is in the pdf file. I did the question, but I'm not sure if its correct. My lecture is using Wiley, and I think it is really confusing service for assignments.

Anyways, my questions are:
Is the question done out right?
Why is there θ given, if I don't really need to use it? Or do I need to use it?

Thanks in advance everyone.

Kind regards
 

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  • #2
Welcome to PF, Angello90!
You have quite an interesting problem. It has to be more complex than you took it to be. The angle matters! If the angle was 90 degrees, for instance, then the suitcase would fall before it made a quarter of a turn. When the angle is smaller, the carousel can spin faster without the suitcase sliding.

It seems to me you have to make a free body diagram of all the forces on the suitcase, resolve them into forces down the ramp and into the ramp (normal). I find these problems make more sense when I take the view from the moving object so there is a centrifugal force rather than a centripetal one. Then you can find the friction force and write the condition that the total force down the ramp is zero - spinning as fast as you can without it slipping. It will be kind of like your u*m*g = m*v^2/r, but you'll have more terms and every term will have a sinθ or cosθ factor.
 
  • #3
Thanks Delphi51 for that, can you tell me whether I am correct with this solution in pdf?
 

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  • #4
I don't think so, Angello. Seems to me you have to think like this:
suitcase.jpg

Both the gravity and centrifugal forces need to be resolved into parallel and normal components. The total normal force N will have two expressions added together (one from Fc and one from Fg).
 

FAQ: Resolving Forces for Periodic Motion in a Suitcase

What is the periodic time of a suitcase?

The periodic time of a suitcase refers to the amount of time it takes for the suitcase to complete one full cycle of its movement. This can include being loaded onto a conveyor belt, being transported on a plane, and being retrieved by its owner.

How is the periodic time of a suitcase measured?

The periodic time of a suitcase can be measured by timing how long it takes for the suitcase to complete one full cycle of its movement, or by using a stopwatch to measure the time it takes for the suitcase to complete a certain distance.

Does the periodic time of a suitcase vary?

Yes, the periodic time of a suitcase can vary depending on factors such as the size and weight of the suitcase, the speed of the conveyor belt or mode of transportation, and any obstacles or delays that may occur during the suitcase's journey.

Why is the periodic time of a suitcase important?

The periodic time of a suitcase is important for understanding and optimizing the efficiency of baggage handling systems in airports and other transportation facilities. It can also impact the overall travel time for passengers and their luggage.

Can the periodic time of a suitcase be affected by external factors?

Yes, external factors such as weather conditions, technical malfunctions, or human error can affect the periodic time of a suitcase. This is why it is important for airports and transportation facilities to have efficient and reliable baggage handling systems in place.

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