- #1
supak111
- 47
- 1
How do I calculate a resonate frequency of a length of pipe submerged totally under water?
Do I just take speed of sound in water which is 1,481m/s at room temp, and decided it by length of pipe in meters multiplied by 4?
so at 20 celsius water and 20cm pipe it would just be: 1481 / (.2 x 4) = 1851.25Hz??
Do I just take speed of sound in water which is 1,481m/s at room temp, and decided it by length of pipe in meters multiplied by 4?
so at 20 celsius water and 20cm pipe it would just be: 1481 / (.2 x 4) = 1851.25Hz??