Resultant pedal force (FRESULTANT) Force tangential to the crank arm

In summary, the data shows that there is a positive torque applied to the crank when the cyclist pedals in the upward direction.
  • #1
david03
2
0
Homework Statement
You have been given pedalling force data for 10 cyclists to analyse. Write a Matlab code to calculate the following for each cyclist:
Throughout the pedal stroke (i.e. additional columns of data):
• Resultant pedal force (FRESULTANT)
• Force tangential to the crank arm (crank arm length = 170 mm) (i.e. the effective pedal force, FEFFECTIVE)
Single values for the pedal stroke:
• Peak torque and angle of peak torque
• Positive and negative work done during the pedal stroke
• Mean power throughout the pedal stroke
• Index of Force effectiveness (IFE)
• Evenness of torque distribution (ETD)
Part 2
Divide the cyclists into two groups based on their ETD values; a good group with ETD ≥ 25%; and a poor group with ETD < 25%. Perform statistical tests to determine if there is a difference between these two groups for each of the remaining six single value variables calculated above. Present the results for each of these six variables as bar charts (presenting the mean and standard deviation for each group)
Notes
The cyclist data is in an excel spreadsheet that can be downloaded from Learn (data_cycle_10.xlsx). Each worksheet contains the data for one cyclist and the five columns to data are:
CRANK crank angle measured clockwise from top dead centre (i.e. vertical pointing upwards)
SPINDLE pedal spindle angle measured anti-clockwise from horizontal
Ft and Fn are the forces applied to the pedals tangential and normal to the pedal surface
TORQUE torque applied to turning the crank arm (TCRANK)
Relevant Equations
attached below as photos
%% part 1
clear all; close all; clc;

torq_crPK = zeros(10,1);
ang_tqPK = zeros(10,1);
ang_powPK = zeros(10,1);
torq_crDS = zeros(10,1);
torq_crUS = zeros(10,1);
WD = zeros(10,1);
WDpos = zeros(10,1);
WDneg = zeros(10,1);%% INPUT VARIABLES
for i=1:10 % cyclist number

% read in the cyclists data
if (i < 10)
data1=xlsread('21WSB302_matlab_report_data.xlsx',['cycle0' num2str(i)],'B10:F370'); % angle-torque data
else
data1=xlsread('21WSB302_matlab_report_data.xlsx',['cycle' num2str(i)],'B10:F370'); % angle-torque data
end

%% PART 1

ang_cr=data1(:,1); % crank angle
torq_cr=data1(:,5); % crank torque

% peak values (10)
[torq_crPK(i,1),]=max(torq_cr);
ang_tqPK(i,1)=ang_cr(i); % peak torque and angle where it occurs
ang_powPK(i,1)=ang_cr(i); % peak power and angle where it occurs

% averages (4&5)
[iDS]=find(ang_cr<=180);
torq_crDS(i,1)=mean(torq_cr(iDS)); % average downstroke torque
[iUS]=find(ang_cr>180);
torq_crUS(i,1)=mean(torq_cr(iUS)); % average upstroke torque

% work done total
WD(i,1)=trapz(deg2rad(ang_cr),torq_cr); % numerical integration of torque wrt angle (in radians)

% positive work done
% create a copy of torq_cr
% find all the negative torques in the copy
% reset the negative torques to zero
% apply trapz to this copy
torq_pos=torq_cr;
ineg=find(torq_cr<0);
torq_pos(ineg)=0;
WDpos(i,1)=trapz(deg2rad(ang_cr),torq_pos);

% negative work done
% create a second copy of torq_cr
% find all the postive torques in the second copy
% reset the positve torques to zero
% apply trapz to this second copy
torq_neg=torq_cr;
ipos=find(torq_cr>=0);
torq_neg(ipos)=0;
WDneg(i,1)=trapz(deg2rad(ang_cr),torq_neg);

end

%% WRITE DATA
headings={'sub','torqPK','ang_tqPK','torqDS','torqUS','powPK','ang_powPK','powMN','workNET','workPOS','workNEG'};
subs=[1:10]';
data_out=[subs torq_crPK ang_tqPK torq_crDS torq_crUS ang_powPK WD WDpos WDneg]; % create a single matrix with all the data first
xlswrite('21WSB302_matlab_report_data.xlsx',headings,'results','I10');
xlswrite('21WSB302_matlab_report_data.xlsx',data_out,'results','I11');
 

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  • #2
You didn't post a diagram of the system, as I asked. Show the crank and pedal, marking the angles and applied forces.
Two things I do not understand in the problem statement:
- it is not clear which way is positive for Ft
- telling you the torque should be unnecessary since you can compute it from the other data… except that it does at least tell you which way Ft is measured.

I am unfamiliar with the language you write the code in. Please explain in algebra how you are calculating the answers.
 

FAQ: Resultant pedal force (FRESULTANT) Force tangential to the crank arm

What is resultant pedal force?

Resultant pedal force (FRESULTANT) refers to the overall force applied to the pedal of a bicycle, taking into account both the downward force (weight) and the tangential force (pushing or pulling) on the crank arm.

How is resultant pedal force calculated?

Resultant pedal force is calculated by using vector addition to combine the downward force (weight) and the tangential force (pushing or pulling) on the crank arm. This results in a single force that represents the overall force applied to the pedal.

Why is resultant pedal force important?

Resultant pedal force is important because it determines the amount of work being done on the bicycle. It also affects the speed and efficiency of the cyclist, as well as the amount of stress placed on the bicycle components.

How does the angle of the crank arm affect the resultant pedal force?

The angle of the crank arm affects the direction and magnitude of the tangential force, which in turn affects the resultant pedal force. A larger angle will result in a greater tangential force and a larger resultant pedal force.

What factors can affect the resultant pedal force?

The resultant pedal force can be affected by various factors such as the weight and strength of the cyclist, the gear ratio, the terrain, and the resistance from the bicycle components. Wind resistance and friction can also play a role in the overall resultant pedal force.

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