- #1
kukumaluboy
- 61
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Homework Statement
A man pushing a toy car causes it to undergo 2 displacements. The first has a magnitude of 150 cm and makes an angle of 120degrees with the positive x axis. The resultant displacement has a magnitude of 140 cm and is directed at an angle of 35 degrees at the positive x axis. Find the magnitude and direction of the second displacement.
The Attempt at a Solution
Displacement A + Displacement B = Displacement R
B = R - A
R = Rx + Ry
R = 140cos35i + 140sin35j
180° - 120° = 60
A = Ay + Ax
A = 150sin60j - 150cos60i (2nd Quad?? Not too sure if need to put negative here)
Hence:
B = Rx + Ry - (Ay + Ax)
B = 140cos35i + 140sin35j - (150sin60j - 150cos60i)
B = (140cos35 +150cos60)i + (140sin35 - 150sin60)j
B = sqrt( Bi^2 + Bj^2 )
B = 196
To find Direction
tetha = taninverse( (140sin35 - 150sin60)/ (140cos35 +150cos60) )
tetha = -14.65 degrees ?? weird??