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~christina~
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[SOLVED] Revolutions per sec (centripital acceleration)
As their booster rockets seperate, space shuttle astronauts typically feel acclerations up to 3g where g= 9.80ms^2. In their training astronauts ride in a device in which they experience such accelrations as centripital accleration. Specifically, the astronaut is fastened securely at the end of a mechanical arm and that turns at constant speed in a horizontal circle.
determine the rotation rate in revolutions per sec required to give a astronaut a centripital accelration of 3.00kg while in a circular motion with the radius of 9.45m
[tex]a_c = v^2/r [/tex]
T= 2pi*r/ v
all I know is that the
[tex]a_c[/tex] = 3.00kg
and that
r= 9.45m
I'm not sure what I do with this though since wouldn't the accelration usually be in m/s^2 but in this case it is in kg...how can this be?
well I also don't have the velocity either...
I was thinking of substituting the centripital accelration equation into the period T equation to get rid of v however I do know that speed is constant but velocity magnitude doesn't change since speed doesn't change but the magnitude I know does..
Can someone help me out with this...
Thanks![Smile :smile: :smile:](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Homework Statement
As their booster rockets seperate, space shuttle astronauts typically feel acclerations up to 3g where g= 9.80ms^2. In their training astronauts ride in a device in which they experience such accelrations as centripital accleration. Specifically, the astronaut is fastened securely at the end of a mechanical arm and that turns at constant speed in a horizontal circle.
determine the rotation rate in revolutions per sec required to give a astronaut a centripital accelration of 3.00kg while in a circular motion with the radius of 9.45m
Homework Equations
[tex]a_c = v^2/r [/tex]
T= 2pi*r/ v
The Attempt at a Solution
all I know is that the
[tex]a_c[/tex] = 3.00kg
and that
r= 9.45m
I'm not sure what I do with this though since wouldn't the accelration usually be in m/s^2 but in this case it is in kg...how can this be?
well I also don't have the velocity either...
I was thinking of substituting the centripital accelration equation into the period T equation to get rid of v however I do know that speed is constant but velocity magnitude doesn't change since speed doesn't change but the magnitude I know does..
Can someone help me out with this...
Thanks