Rewrite polar equation as Cartesian (trig identities)

In summary, by using the trigonometric identities for (cos theta cos phi) and (cos theta sin phi) and the Pythagorean identity (cos^2 + sin^2 = 1), we can rewrite the given equations in terms of x and y as follows: x = 2acos(theta - pi/3)cos(theta) and y = 2acos(theta - pi/3)sin(theta). By multiplying both sides of the r function by r and substituting y=rsin(theta) and x=rcos(theta), we can simplify the equations to x = 2rcos(theta) and y = 2rsin(theta). This has a geometric interpretation as the coordinates (x,y) representing a
  • #1
craig16
21
0

Homework Statement



x=2acos(theta- pi/3)cos(theta)
y=2acos(theta- pi/3)sin(theta)

Write everything in terms of x and y

Homework Equations



cos(a-b)=cos(a)cos(b)+sin(a)sin(b)
sina/cosa=tana

etc...

The Attempt at a Solution



I've tried a lot of rearranging, can't figure it out.
 
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  • #2
I'm not sure I understand. Are you trying to write [tex]\theta\ [/tex] and a in terms of x and y?

If so, take a look at x/y or y/x.
 
  • #3
craig16 said:

Homework Statement



x=2acos(theta- pi/3)cos(theta)
y=2acos(theta- pi/3)sin(theta)

Write everything in terms of x and y

You'll be able to make good use of: http://en.wikipedia.org/wiki/List_of_trigonometric_identities

Particulary the formulas for (cos theta cos phi) and (cos theta sin phi).
Combine these with the standard (cos^2 + sin^2) = 1.
 
  • #4
Yaaa, i figured it out.

Just multiplying both sides of the r function by r, then subbing in y=rsin(theta) and x=rcos(theta) then using sin^2 + cos^2 =1 will make it just in terms of x and y.
 
  • #5
craig16 said:
Yaaa, i figured it out.

Just multiplying both sides of the r function by r, then subbing in y=rsin(theta) and x=rcos(theta) then using sin^2 + cos^2 =1 will make it just in terms of x and y.

So what did you end up with?
And do you have a geometric interpretation?
 

FAQ: Rewrite polar equation as Cartesian (trig identities)

How do you convert a polar equation into a Cartesian equation using trigonometric identities?

To convert a polar equation to a Cartesian equation, we can use the following trigonometric identities:
x = r cos θ
y = r sin θ
where r represents the distance from the origin and θ represents the angle from the positive x-axis to the point.
Using these identities, we can rewrite the polar equation in terms of x and y.

Can all polar equations be rewritten using trigonometric identities?

Yes, all polar equations can be rewritten using trigonometric identities. These identities help us to convert the polar coordinates (r, θ) into Cartesian coordinates (x, y).

What is the purpose of rewriting a polar equation as a Cartesian equation?

Rewriting a polar equation as a Cartesian equation can be useful in graphing and analyzing the equation. It allows us to plot the equation on a rectangular coordinate system and easily identify important points such as the x and y-intercepts, symmetry, and asymptotes.

How do you use the Pythagorean identity to rewrite a polar equation as a Cartesian equation?

The Pythagorean identity, sin² θ + cos² θ = 1, can be used to rewrite a polar equation as a Cartesian equation. For example, if the polar equation is r = 2 cos θ, we can square both sides to get r² = 4 cos² θ. Then, using the Pythagorean identity, we can replace cos² θ with 1 - sin² θ to get r² = 4(1 - sin² θ). Finally, we can use the identity x² + y² = r² to rewrite the equation in terms of x and y.

Are there any special cases to consider when rewriting a polar equation as a Cartesian equation?

Yes, there are a few special cases to consider when rewriting a polar equation as a Cartesian equation. These include equations that involve the polar coordinates (r, θ) being raised to a power, equations with multiple angles, and equations with negative angles. In these cases, we may need to use additional trigonometric identities and algebraic manipulations to rewrite the equation in terms of x and y.

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