Rewriting Equation 15: Two Transverse Waves Moving in Opposite Directions

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The discussion focuses on rewriting the wave equation, specifically Equation 15, to express it as the sum of two transverse waves moving in opposite directions. The original equation involves a combination of sine and cosine functions, which can be separated using trigonometric identities. Participants suggest using the identity for the product of sine and cosine to facilitate this transformation. The key approach involves setting appropriate values for Alpha and Beta in the identity to derive the desired form. Understanding and applying these trigonometric identities is essential for solving the problem related to standing waves on a wire.
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Homework Statement



Show that the solution to the wave equation, Equation 15, can be rewritten as the sum of two transverse waves moving in opposite directions along the wire.

Equation 15:y(x,t) = A(sin(2*pi*f*x)/v))*cos(2*pi*f*t)


Homework Equations



Superposition: y(x,t) = f(x-ct) + g(x+ct)
Period: T = (1/f) = (2 * pi/omega)
Wavelength = (2* pi)/k

The Attempt at a Solution



I really just don't know where to start. Do I need a trig identity? I am completely not sure how to separate it into two terms that use like superposition for example. This equation shown above is not the standard wave equation but with variables substituted inside. I am trying to solve this or show for the topic of standing waves on a wire.
 
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You need to invert the trig identities for \sin(A\pm B) to derive a formula for the product \sin A \cos B.
 
So, what do you mean by inverting the trig identity?

Could you possibly, show me how to start this question?

sin Alpha cos β = ½[sin (Alpha + β) + sin (Alpha − β)] <--- This is a trig identity I should be using?

So would i just set Alpha = 2*pi*f*x/v and beta = 2*pi*f*t?
 
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