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CrossFit415
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x[itex]\stackrel{Lim}{\rightarrow}[/itex]infinity ([itex]\sqrt{x^{2}+1}[/itex])[itex]-1[/itex]
Couldn't I just inset 0 for x and end up getting [itex]\sqrt{1}[/itex]?
The book tells me to rewrite this problem by its conjugate.
My question is why? Thanks
Couldn't I just inset 0 for x and end up getting [itex]\sqrt{1}[/itex]?
The book tells me to rewrite this problem by its conjugate.
My question is why? Thanks
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