Right & Left Hand Limits of (sinx)^tanx: Indeterminate Form 0^0

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In summary, the right hand limit of (sinx)^tanx as x approaches 0 is 1, while the left hand limit does not exist due to the function not being defined for negative values of x. This can be seen from the graph of the function, where approaching 0 from the right results in a limit of 1, but approaching from the left results in an undefined limit.
  • #1
erisedk
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What is the right hand and left hand limit of (sinx)^tanx?
I know this is an indeterminate form 0^0 but what are the RHL and LHL because though I intuitively know that 0^0 is indeterminate, I don't understand what the right hand and left hand limits are?
 
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  • #2
As I implement!

$$\lim_{x\rightarrow 0}sinx^{tanx}$$

look at the graph of the function

http://www.wolframalpha.com/input/?i=sin x^{tan x}

And this is intuitively reasonable,
Let us assume a very small value approaching to zero for theta [in radians] , say 0.00000001, then the value will be very close to 1
This is the limit from the right .
And the limit from the lift doesn't exist since you x^x is not always valid for negative numbers..,Hope that is right and what you are looking for ,,
:)
 
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  • #3
It doesn't make sense to talk about "limits" at all without saying what x itself if going to. I presume here you mean "limit as x goes to 0". The "left hand limit" would be as x approaches 0 "from the left" on the number line- that is, x is always negative. The "right hand limit" would be as x approaches 0 "from the right on the number line- x is always positive.

You should be able to see from your graph that if x is approaching 0 "from the right" or "from above", then f(x) goes to 1 while it cannot approach 0 "from the left" or "from below" because, as Maged Saeed said, sin(x)tan(x) is not defined there.
 
  • #4
Ok thanks :D
 

FAQ: Right & Left Hand Limits of (sinx)^tanx: Indeterminate Form 0^0

What is the indeterminate form 0^0?

The indeterminate form 0^0 is a mathematical expression that results in an undefined value when both the base and the exponent are equal to 0. This means that it is impossible to determine the value of 0^0 without further context or information.

Why is (sinx)^tanx an example of the indeterminate form 0^0?

(sinx)^tanx is an example of the indeterminate form 0^0 because when x is equal to 0, both the sine and tangent functions are equal to 0. Therefore, the expression becomes 0^0, which is an indeterminate form.

How do you solve for the right and left hand limits of (sinx)^tanx when x approaches 0?

To solve for the right and left hand limits of (sinx)^tanx when x approaches 0, we can use the L'Hôpital's rule. This rule states that the limit of a fraction can be determined by taking the limit of the numerator and denominator separately. By applying this rule, we can determine that the right hand limit is equal to 1, and the left hand limit is equal to 0.

Can the indeterminate form 0^0 be solved using algebraic manipulation?

No, the indeterminate form 0^0 cannot be solved using algebraic manipulation alone. This is because any number raised to the power of 0 is equal to 1, and any number raised to the power of 0 is equal to 0. Therefore, when both the base and the exponent are equal to 0, it is impossible to determine the value of the expression using algebraic manipulation.

What is the significance of understanding the concept of indeterminate forms in mathematics?

Understanding the concept of indeterminate forms is crucial in mathematics as it allows us to evaluate complex or undefined limits that cannot be solved using basic algebraic methods. It also helps us to identify situations where further analysis or information is needed to determine the value of an expression. Additionally, understanding indeterminate forms can help us to better understand the behavior of functions and their limits, which is essential in many areas of mathematics and science.

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