- #1
OmniNewton
- 105
- 5
Homework Statement
Given the following diagram
If the crate produces a force of gravity of 491 N from the center of gravity G, determine the normal force on both of the wheels and the magnitude and direction of the minimum force required at the grip B needed to lift the load.
Homework Equations
Fx = 0;
Fy= 0;
MB = 0;
The Attempt at a Solution
Sign Convention: Up and to the right is positive and counter clockwise is positive.
from Fx = 0
0= 2Ax - FBcos(theta) (equation 1)
from Fy = 0
0= FBsin(theta) - 491N + 2Ay (equation 2)
from MB = 0
0 = -2Axcos60(0.1) +2 Aysin60(0.1) - (491cos30)(0.6) (equation 3)
from 1
Ax= 0.5FBcos(theta) (1A)
from 2
Ay = 0.5(491N-FBsin(theta) (2A)
Substitute 1A and 2A into 3
After Simplifying I have
-0.05FBcos(theta)-0.0866FBsin(theta) =212.61
I am now stuck as to how to proceed. I am wondering if my initial free body diagram is flawed. Does the wheel at A produce a horizontal force Ax and a Vertical force Ay? Or is Ay the only force produced. The problem with my equations is I seem to have to many unknowns.