- #1
QuantumJG
- 32
- 0
Show [tex] \mathbb{Z} [ \sqrt{2} ] [/tex] = [tex] \{ a + b \sqrt{2} | a,b \in \mathbb{Z} \} [/tex] has infinitely many units.
I started by taking an element:
[tex] a + b \sqrt{2} \in \mathbb{Z} [ \sqrt{2} ] [/tex]
and finding an inverse
[tex] \left( a + b \sqrt{2} \right) ^{-1} [/tex]
such that the product gives zero and tried to show any element works. But I'm not sure about doing this.
I started by taking an element:
[tex] a + b \sqrt{2} \in \mathbb{Z} [ \sqrt{2} ] [/tex]
and finding an inverse
[tex] \left( a + b \sqrt{2} \right) ^{-1} [/tex]
such that the product gives zero and tried to show any element works. But I'm not sure about doing this.