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dlingo
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Advanced Road Bank question
There is a road bank designed for 60km/hr (16.7 m/s) with a radius of 70m and no friction. What is the top speed with a mew of 0.8[tex]\mu[/tex] ?
G=gravitational constant
V=16.7m/s
Tan[tex]\theta[/tex]=V^2/(R*G)
Fc=(M*V^2)/R
First I calculated the angle at which the car won't move with no friction and I got 22.124
Then I started filling in what I knew:
Fnormal:=(G*sin([tex]\theta[/tex]))+(Fc*Sin(90-[tex]\theta[/tex])) The component of gravity added to a component of Centripetal force.
then:
Ffriction:=Mew*Fnormal
Fc:=Ffriction+the component of fnormal pushing back against the Fc.
(M*V^2)/R=Mew*((G*sin([tex]\theta[/tex]))+(Fc*Sin(90-[tex]\theta[/tex])))the component of fnormal pushing back against the Fc.
But I don't know if I'm on the right track or completely wrong.
Homework Statement
There is a road bank designed for 60km/hr (16.7 m/s) with a radius of 70m and no friction. What is the top speed with a mew of 0.8[tex]\mu[/tex] ?
G=gravitational constant
V=16.7m/s
Homework Equations
Tan[tex]\theta[/tex]=V^2/(R*G)
Fc=(M*V^2)/R
The Attempt at a Solution
First I calculated the angle at which the car won't move with no friction and I got 22.124
Then I started filling in what I knew:
Fnormal:=(G*sin([tex]\theta[/tex]))+(Fc*Sin(90-[tex]\theta[/tex])) The component of gravity added to a component of Centripetal force.
then:
Ffriction:=Mew*Fnormal
Fc:=Ffriction+the component of fnormal pushing back against the Fc.
(M*V^2)/R=Mew*((G*sin([tex]\theta[/tex]))+(Fc*Sin(90-[tex]\theta[/tex])))the component of fnormal pushing back against the Fc.
But I don't know if I'm on the right track or completely wrong.
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