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bensondros
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Homework Statement
Find the speed v of the rocket when the mass of the rocket = m. The rocket starts from rest at with mass M. Fuel is ejected at speed u relative to the rocket.
Homework Equations
m1v1 = m2v2
The Attempt at a Solution
In the textbook, it starts off with a moving rocket with mass m and speed v. The fuel is given the mass (-dm) which is positive. So after a short time dt, the mass of the rocket changes to m+dm and speed v+dv. The mass of the ejected fuel is (-dm) and since it ejects with speed u relative to the rocket traveling at speed v, the ejected fuel travels at speed v-u, which can be positive or negative depending on which of v or u is larger.
Writing down the equation of conservation of momentum:
mv = (m+dm)(v+dv) + (-dm)(v-u)
which then leads to
m dv = -u dm
After a few steps, we get:
v2-v1 = u ln(m1/m2)
That all looks fine and understandable. However, it mentions in the book that I am free to define dm to be positive, and then subtract it from the rocket's mass, and have dm get shot out the back. So I have decided to try it.
Writing down the equation of conservation of momentum:
mv = (m-dm)(v+dv) + dm(v-u)
which then leads to
m dv = u dm (note that at this point, the equation is already different from before)
Moving the variables around and integrating v from v1 to v2, m from m1 to m2 as before, I obtained:
v2-v1 = u ln(m2/m1)
which is clearly wrong because m2<m1, so
ln(m2/m1) < 0
but
v2 > v1
So what went wrong there?