Rocket Motion: Solving the Rocket Equation for Lift-Off

In summary, the conversation is about a question posed in class for extra credit, involving a rocket with an initial mass of 70000kg and a fuel burn rate of 250kg/s with an exhaust velocity of 2500m/s. The equation used to solve the problem is discussed and suggestions are given on how to approach it. Ultimately, it is suggested to calculate the force of the rocket and set it equal to its weight to determine the time it will take for the rocket to lift off, which is estimated to be around 25 seconds.
  • #1
SlickJ
6
0
This question was posed in class the other day for extra credit:

A rocket with initial mass 70000kg burns fuel at a rate of 250kg/s; it has an exhaust velocity of 2500m/s. If the rocket is at rest, how long after the engines fire will the rocket lift off?

I've been trying to solve it using some variation of the rocket equation:
v=v(exhaust) * ln(M(0)/M(t)) - gt
but to no success.
Any hints or help would be greatly appreciated
 
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  • #2
There is a problem with the equation you are using
it is r (rate of burning the fuel) for g you used, also it is dimensionally incorrect we can have log of only natural numbers.
If it works that's Ok, otherwise try by equating force by the ejected gass to mass of rocekt at the moment.
 
  • #3
SlickJ said:
This question was posed in class the other day for extra credit:

A rocket with initial mass 70000kg burns fuel at a rate of 250kg/s; it has an exhaust velocity of 2500m/s. If the rocket is at rest, how long after the engines fire will the rocket lift off?

I've been trying to solve it using some variation of the rocket equation:
v=v(exhaust) * ln(M(0)/M(t)) - gt
but to no success.
Any hints or help would be greatly appreciated

Be careful. The equation of your rocket is:

[tex] v=2500\cdot ln\Big(\frac{70000}{70000-250t}\Big)-9.8t[/tex]

There is an interval of velocities 0<t<47.9 s in which v<0. The rocket will start to lifting off when v>0 or t>47.9 s. (solve numerically the equation v=0, you will obtain t=0 and t=47.9 s).
 
  • #4
Thanks both of you for your help, very much appreciated.
 
  • #5
I think you're all making this much too complicated.
Just calculate the force the rocket produces using the equation force = change in momentum / time, with knowledge of the fact that momentum is mass times velocity. The weight of the rocket is given by acceleration due to gravity x (original mass of rocket - (rate at which the rocket loses mass x time). Set the weight of the rocket to equal the its force of propulsion (which you already calculated) and solve for time. At that time, the force of thrust will balance the rocket's weight and immediately afterwards it will start lifting off.
 
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  • #6
I get about 25 seconds.
 

FAQ: Rocket Motion: Solving the Rocket Equation for Lift-Off

1. What is the rocket equation and why is it important for lift-off?

The rocket equation is a mathematical formula that describes the motion of a rocket and how it is affected by the forces of gravity and thrust. It is important for lift-off because it helps us understand how much thrust is needed to overcome the force of gravity and achieve liftoff.

2. How do you solve the rocket equation?

The rocket equation can be solved by using the equation: Δv = ve * ln(m0/mf), where Δv is the change in velocity, ve is the exhaust velocity, m0 is the initial mass of the rocket, and mf is the final mass of the rocket. This equation can be used to calculate the amount of fuel needed for a rocket to reach a desired velocity.

3. What factors affect rocket motion and lift-off?

There are several factors that affect rocket motion and lift-off, including the weight of the rocket and its payload, the amount of thrust generated by the rocket engine, and the direction and stability of the rocket's trajectory. Other factors such as air resistance and wind conditions can also play a role in the rocket's motion.

4. How does the mass of the rocket change during lift-off?

During lift-off, the mass of the rocket decreases as fuel is burned and ejected from the rocket. This decrease in mass affects the rocket's acceleration and velocity, as described by the rocket equation. As the rocket continues to burn fuel and lose mass, its acceleration and velocity will also change.

5. What are some real-world applications of the rocket equation?

The rocket equation has many real-world applications in the field of aerospace engineering. It is used to design and calculate the necessary thrust and fuel requirements for rockets and spacecrafts to achieve liftoff and enter orbit. It is also used in the development of propulsion systems for rockets and in the planning of space missions.

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