Rolle's theorem -> Differentiability

[Spiralshell]

Homework Statement

So I'm doing problems where I have to verify Rolle's hypotheses. I am only having trouble with the differentiability part. My professor wants me to prove this. So for example,
f(x)=√(x)-(1/3)x [0,9]

Homework Equations

none

The Attempt at a Solution

1.) I know the function is continuous because root functions are continuous on their domains and polynomials are continuous everywhere therefore the difference of two continuous functions is continuous.

2.) What could I say about it being differentiable?
My GUESS: it is defined everywhere on its domain [0,9] and continuous it is therefore differentiable on its domain [0,9]?

I am only stuck on 2.) so no need to go further on the problem.

 

[HallsofIvy]

No. Saying that a function is "defined and continuous" on a domain does NOT mean that it is differentiable on the interval. For example, |x| is "defined and continuous" for all x but is not differentiable at x= 0.

It's hard to tell you how you should answer this without knowing what you about derivatives. IF you know that the derivative of $x^n$ is $nx^{n-1}$ then it should be easy to tell what the derivative of $x^{1/2}- x/3$ is and so where it is differentiable.

(It is NOT differentiable on [0, 1] but Rolle's theorem does not require it to be.)

 

[Spiralshell]

I know the derivative to the function. I also know chain rule and the limit definition as well quotient rule, etc. So the way my professor explained is that I have to verify I can differentiate over the interval given. In this case [0,9].

So I know f'(x)=1/(2√x)-(1/3)

I just don't understand how I verify that is differentiable over [0,9].

Here is how he gave me Rolle's Theorem (very simply):
1.) f is continuous on [a,b] (Prove it!)
2.) f is differentiable on (a,b) (Prove it!)
3.) f(a)=f(b) then if all 3 conditions are met a<c<b such that c belongs to (a,b) and that f'(c)=0.

I hope this helps you understand my situation. I am only stuck on 2.)... The rest is I understand.

Also, thank you for replying. I appreciate all the help I can get.

 

[jbunniii]

I know the derivative to the function. I also know chain rule and the limit definition as well quotient rule, etc. So the way my professor explained is that I have to verify I can differentiate over the interval given. In this case [0,9].

So I know f'(x)=1/(2√x)-(1/3)

I just don't understand how I verify that is differentiable over [0,9].

Well, you have computed a formula for the derivative. Are there any values of $x$ in $[0,9]$ that cause problems?